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Marina86 [1]
3 years ago
8

Jeff is purchasing a car for $29,175 that will depreciate in value 7.5% each year.

Mathematics
1 answer:
beks73 [17]3 years ago
5 0

Answer:

Step-by-step explanation:

figure that S*** out your self jeez

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Simplify:<br> 1y- 2x - 3y + 4x
dangina [55]

Answer:

2x - 2y

Step-by-step explanation:

Multiply by 1

combine like terms

Combine the second

rearrange terms

Then you should come up with the sloution 2x - 2y

4 0
2 years ago
(N^3 - N^4) - (3n^3- 7n^4)
Free_Kalibri [48]
If you would like to solve (n^3 - n^4) - (3n^3 - 7n^4), you can do this using the following steps:

(n^3 - n^4) - (3n^3 - 7n^4) = <span>n^3 - n^4 - 3n^3 + 7n^4 = n^3 - 3n^3 - n^4 + 7n^4 = -2n^3 + 6n^4
</span>
The correct result would be <span>-2n^3 + 6n^4.</span>
3 0
3 years ago
If you read 4/9 of a page in 3/5 minutes what’s your unit rate page per minute
Vikentia [17]

Answer:

12/45

Step-by-step explanation:

The unit rate is 12/45, because 4 times 3 is 12, and 9 times 5 is 45.

5 0
2 years ago
Find the length of side x in simplest radical form with a rational denominator.
devlian [24]

Answer:

x = 2√2

Step-by-step explanation:

This is a 45-45-90 triangle. This means that if the legs are x, then the hypotenuse is x√2.

In the case, the hypotenuse is already 4. So we have the equation:

x√2 = 4

Multiply both sides by √2

2x = 4√2

Divide both sides by 2

x = 2√2

5 0
3 years ago
A gambler has a fair coin and a two-headed coin in his pocket. He selects one of the coins at random. (a) When he flips the coin
Aleks04 [339]

Answer:

a) probability of choosing heads= 1/2 (50%)

b)  probability of choosing the fair coin knowing that it showed heads is= 1/3 (33.33%)

Step-by-step explanation:

Since the unfair coin can have 2 heads or 2 tails , and assuming both are equally possible . then

probability of choosing the fair coin  (named A)= 1/2

probability of choosing an unfair coin with 2 heads (named B)= (1-1/2)*1/2= 1/4

probability of choosing an unfair coin with 2 tails (named C)= (1-1/2)*(1-1/2)= 1/4

then

probability of choosing heads= probability of choosing A * probability of getting heads from A + probability of choosing B * probability of getting heads from B + probability of choosing C * probability of getting heads from C =

1/2*1/2 + 1/4*1 + 1/4*0 = 2/4 = 1/2

the probability of choosing the fair coin knowing that it showed heads is

P(A/B) = P(A∩B)/P(B)

denoting event A= the coin is fair and event B= the result is heads

P(A∩B) = 1/2*1/2 = 1/4

but since we know now that that the unfair coin is not possible , the probability of choosing heads is altered:

P(B)=probability of choosing heads= probability of choosing A * probability of getting heads from A + probability of choosing B * probability of getting heads from B  = 1/2*1/2+1/2*1 = 3/4

then

P(A/B) = P(A∩B)/P(B)  = (1/4)/(3/4) = 1/3

then the probability is 1/3

8 0
3 years ago
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