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inn [45]
2 years ago
8

Please help me. justify your answers!​

Mathematics
2 answers:
azamat2 years ago
7 0

Answer:

g. True

h. False

i. False

Step-by-step explanation:

<em>g.</em>

\frac{1}{14} is half of \frac{1}{7}

This would be true because half of a number can be found by multiplying by \frac{1}{2}

If you multiplied \frac{1}{7} * \frac{1}{2}

The numerator is 1 * 1 which is 1

And then the denominator is 7 * 2 which is 14

That would give you \frac{1}{14}

<em>h.</em>

The products of two reciprocals is 0

This is not true

Reason being, reciprocals are just the number flipped. If you times the number by itself, you don't get 0, you get 1.

Ex: \frac{2}{8}

Its reciprocal is \frac{8}{2}

So multiply them together

\frac{2}{8}* \frac{8}{2}

2 * 8 = 16

8 * 2 = 16

\frac{16}{16} = 1

<em>i.</em>

A whole number does not have a reciprocal

This is incorrect. If you think about it, a whole number is just the number, over 1

Ex: \frac{6}{1}

This is still a whole number even though its written in fraction form because if you divide 6 by 1, your still going to get 6.

If you an write it as a fraction, it has a reciprocal.

The reciprocal in this case would be \frac{1}{6}

I hope this helps, don't be afraid to reach out with any further questions!

laila [671]2 years ago
4 0

Answer:

T, F, F

Step-by-step explanation:

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Given : A inequality is given to us . The inequality is 19 ≥ t + 18 ≥ 11 .

To Find : The correct option between the given ones . To write the compound inequality with integers .

Solution : The given inequality to us is 19 ≥ t + 18 ≥ 11 . Let's simplify them seperately .

\red{\tt Case\:1}

⇒ 19 ≥ t + 18 .

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⇒ t ≤ 1 = 1 ≥ t . ..................(i)

\red{\tt Case\:2}

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<u>On</u><u> </u><u>combing</u><u> </u><u>(</u><u>i</u><u>)</u><u> </u><u>&</u><u> </u><u>(</u><u>ii</u><u>)</u><u> </u><u>.</u>

\Large\boxed{\green{\bf \red{\longmapsto} 1 \geqslant t \geqslant -7 }}

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