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Snezhnost [94]
3 years ago
10

What is the range of the exponential function shown below

Mathematics
2 answers:
kvv77 [185]3 years ago
6 0

Answer:

The correct option is C.

Step-by-step explanation:

Range is the set of output or the values of the function.

The given function is

f(x)=9\cdot 2^x

If a exponential function is defined as g(x)=a^x, where a>0, then the value of g(x) is always greater than 0, g(x)>0.

It means,

2^x>0

Multiply both sides by 9.

9\cdot 2^x>9\cdot 0

9\cdot 2^x>0

f(x)>0

The value of the function f(x) is always greater than 0, therefore the range of the function is

Range = { y | y>0}

Hence the correct option is C.

Vsevolod [243]3 years ago
3 0

Answer : y>0

f(x) = 9*2^x

f(x) is an exponential function

f(x) = 9*2^x

When we plug in positive value for x , the value of y is positive

When we plug in negative value for x , the value y is also positive

So for any value of x, the y value is positive always.

Range is the set of y values for which the function is defined

y values are positive , so range is y >0

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The sum of the n numbers divided by n (which is the average) equals m^2. Then, the sum of the n numbers equals nm^2.
The average of m+n numbers which is the sum of the m numbers plus the sum of the n numbers divided by (m+n) equals (mn^2+nm^2)/(m+n). This is mn(n+m)/(m+n). Then the factor (m+n) can be ruled out and the result is mn.
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3 years ago
What is the answer for the equation 4|x+1/3|=20 ?
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I hope this helps you...

6 0
3 years ago
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A number has 2,5 and 7 as its prime factors. what are the four smallest values it and take​
MA_775_DIABLO [31]

Answer:

  70, 140, 280, 350

Step-by-step explanation:

Obviously, it must have the factors 2, 5, 7 as a minimum, so the smallest value is 2×5×7 = 70.

Any of these primes can be added to the product. In increasing order, the smallest additional factors will be 2, 4, 5, 7, 8, 10, ...

So, the four smallest numbers with prime factors of 2, 5, and 7 are ...

  70 = 2·5·7

  140 = 2²·5·7

  280 = 2³·5·7

  350 = 2·5²·7

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3 years ago
What is the equation of the epicycloid formed by a circle with radius 6 rolling counterclockwise around a circle with radius 12
Ilya [14]

Answer:

Step-by-step explanation:

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3 0
3 years ago
The population of Henderson City was 3,381,000 in 1994, and is growing at an annual rate 1.8%
liq [111]
<h2>In the year 2000, population will be 3,762,979 approximately. Population will double by the year 2033.</h2>

Step-by-step explanation:

   Given that the population grows every year at the same rate( 1.8% ), we can model the population similar to a compound Interest problem.

   From 1994, every subsequent year the new population is obtained by multiplying the previous years' population by \frac{100+1.8}{100} = \frac{101.8}{100}.

   So, the population in the year t can be given by P(t)=3,381,000\textrm{x}(\frac{101.8}{100})^{(t-1994)}

   Population in the year 2000 = 3,381,000\textrm{x}(\frac{101.8}{100})^{6}=3,762,979.38

Population in year 2000 = 3,762,979

   Let us assume population doubles by year y.

2\textrm{x}(3,381,000)=(3,381,000)\textrm{x}(\frac{101.8}{100})^{(y-1994)}

log_{10}2=(y-1994)log_{10}(\frac{101.8}{100})

y-1994=\frac{log_{10}2}{log_{10}1.018}=38.8537

y≈2033

∴ By 2033, the population doubles.

4 0
3 years ago
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