There are three partial products in part a because both values, 273 and 346, have all numerical values, that aren't 0, so they can be multiplied and a value will be added.
There are only 2 partial products in part b because in 306, the tens place is worth 0 and anything times 0 = 0. There will be nothing to add for that value.
First, find the difference between each number in the sequence.... 34 - 25 = 9. 25 - 16 = 9 and 16 - 7 = 9... So, there is a constant difference of 9 between each number of the sequence. To find the 30th term, you could expand the sequence out to 30 (which is a good way to check your answer, but tedious)... So, simply add the 1st value of the sequence to the difference and multiply by 30 to find your 30th value.... 7 + 9 x 30 = 16 x 30 = 480.
Therefore, the 30th term is 480.
The domain for N is All integers where n ≥ 1
<u>Solution:</u>
According to statement a1 = 2 and r = 4. This shows that r is greater than 1.
If r is greater than 1 than it includes integers greater than 1 or equal to 1. It does not include all the real numbers because real numbers include negative numbers also.
If starting value is 2, if we put n=0, then we get 2, but if we put a negative value than we would get a number which is not a part of our sequence.
Thus the domain of n is All integers where n greater than or equal to 1
Answer:
2x-12+5=3x-3
1. subtract 3x-2x
-12+5=x-3
2.-12 add to 5
-7=x-3
3. add three to seven
-4=x
Step-by-step explanation:
Answer:
x=-30
Step-by-step explanation:
We need to get rid of all the denominators in this equation.
This can be achieved by multiplying both the left and the right side by the Least Common Denominator.
In our example, the LCD is equal to .We need to get rid of all the denominators in this equation.
This can be achieved by multiplying both the left and the right side by the Least Common Denominator.
In our example, the LCD is equal to 3 .