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MAXImum [283]
3 years ago
9

You are spreading fertilizer on a golf course at the rate of 40 pounds per 10,000 square feet. If the course is 320 acres, how m

any tons of fertilizer will be needed?
Mathematics
1 answer:
Marianna [84]3 years ago
3 0

Answer:

The correct answer is B: 28 tons



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18+ (-30)<br> Integers help plssss
Neko [114]

Answer: -12

Step-by-step explanation: To solve this problem, we can first start by rewriting the problem. When we add a negative, that's exactly the same thing as subtracting so we can make the problem easier to understand.

18 + (-30) → 18 - 30

To find the answer to this problem, let's first find out how many jumps it get's to 0 from 18. It would take 18 jumps and there is 12 jumps left over. Then, we would subtract 12 from 0 and we would get -12 as our answer. Therefore, 18 + (-30) = -12.

6 0
3 years ago
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What are the dimensions of the rectangle?
sveticcg [70]
14 units x 16 units.
3 0
3 years ago
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Can someone please help me with this question and show the steps?
Katena32 [7]
<h2>Answer:</h2>

D. \ 408in^2

<h2>Step-by-step explanation:</h2>

This is a square pyramid because it's a solid having a square base. The point up the pyramid is called the apex and is directly above the middle of the square base. The surface area of a solid is the total area of its outer surface. If we unfold this pyramid, we'll get one square and four identical triangles. So the surface are can be calculated as follows:

s=s_{square}+4s_{triangle}

FOR THE SQUARE:

s_{square}=L^2 \\ \\ L=12in \\ \\ s_{square}=12^2=144in^2

FOR THE TRIANGLE:

s_{triangle}=\frac{bh}{2} \\ \\ b=12in \\ h=11in \\ \\ s_{triangle}=\frac{12\times 11}{2}=66in^2

Finally:

s=s_{square}+4s_{triangle} \\ \\ s=144+4(66) \\ \\ s=144+264 \\ \\ \boxed{s=408in^2}

7 0
3 years ago
Pls answer guys! Pls help me guys
ira [324]
It's the 2,7,3,2 one or the third one
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3 years ago
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PLEASE PLEASE ANSWER!
muminat

The area of the shaded region is $8(\pi \ -\sqrt{3})\ \text{cm}^2.

Solution:

Given radius = 4 cm

Diameter = 2 × 4 = 8 cm

Let us first find the area of the semi-circle.

Area of the semi-circle = \frac{1}{2}\times \pi r^2

                                      $=\frac{1}{2}\times \pi\times 4^2

                                      $=\frac{1}{2}\times \pi\times 16

Area of the semi-circle = $8\pi cm²

Angle in a semi-circle is always 90º.

∠C = 90°

So, ABC is a right angled triangle.

Using Pythagoras theorem, we can find base of the triangle.

AC^2+BC^2=AB^2

AC^2+4^2=8^2

AC^2=64-16

AC^2=48

AC=4\sqrt{3} cm

Base of the triangle ABC = 4\sqrt{3} cm

Height of the triangle = 4 cm

Area of the triangle ABC = \frac{1}{2}\times b \times h

                                          $=\frac{1}{2}\times 4\sqrt{3}  \times 4

Area of the triangle ABC =  8\sqrt{3} cm²

Area of the shaded region

                   = Area of the semi-circle – Area of the triangle ABC

                   = $8\pi \ \text{cm}^2-8\sqrt{3}\ \text{cm}^2

                   = $8(\pi \ -\sqrt{3})\ \text{cm}^2

Hence the area of the shaded region is $8(\pi \ -\sqrt{3})\ \text{cm}^2.

3 0
3 years ago
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