Question

What is the solution to the system of equations below?

Answer 1

Answer: Infinite solutions.

Step-by-step explanation:

$y=-2x-6\\2y=-4x-12$

Plug the value of y into the second equation.

$\\ 2(-2x-6)=-4x-12\\-4x-12=-4x-12$

Add 12 on both sides.

$-4x-12+12=-4x-12+12\\-4x=-4x$

Add 4x on both sides.

$-4x+4x=-4x+4x$

$0=0$

Answer 2

Answer:

Infinitely many solutions

Step-by-step explanation:

The equation, when set up will be  

2(-2x-6)=-4x-12  

-4x-12=-4x-12

   +12       +12  Add 12 to both sides

------------------------

-4x=-4x  Divide by -4 to both sides

 0=0 You get zero equals zero

   Have a good day and stay safe!