All categories

3 years ago

Alex $8000 in a savings account that earns 3.25 % annually. How much will he earn in interest in 6 months?

Mathematics

1 answer:

kotegsom [21]3 years ago

6 0

<h3>Answer: $130</h3>

=======================================================

Explanation:

I'm assuming the bank is using simple interest (instead of compound interest).

If so, then,

i = P*r*t

i = 8000*0.0325*0.5

i = 130

The amount of interest is $130

In the formula above, I used

P = 8000 = amount deposited
r = 0.0325 = annual interest rate in decimal form
t = 6/12 = 0.5 years, which means you don't use t = 6. We don't use t = 6 because the interest rate is on an annual basis, and not a 6-month basis.

You might be interested in

By Faraday's Law, if a conducting wire of length ℓ meters moves at velocity v m/s perpendicular to a magnetic field of strength

andrew11 [14]

V = -Bρv
dV/dv = -Bρ = -8 x 0.7 = -5.6

4 0

4 years ago

D. (1/2)n +7 = (n+14)/2

TEA [102]

Answer:

n=-14

Step-by-step explanation:

4 0

3 years ago

9. Put these numbers in greatest to least order: 2/3, 60%, 0.06, 3/4

Iteru [2.4K]

Step-by-step explanation:

0.06
60%
2/3
3/4

hope it's right :)

8 0

3 years ago

A closed, rectangular-faced box with a square base is to be constructed using only 36 m2 of material. What should the height h a

kkurt [141]

Answer:

$b=h=\sqrt{6}$ m

Step-by-step explanation:

Let

Bas length of box=b

Height of box=h

Material used in constructing of box=36 square m

We have to find the height h and base length b of the box to maximize the volume of box.

Surface area of box= $2b^2+4bh$

$2b^2+4bh=36$

$b^2+2bh=18$

$2bh=18-b^2$

$h=\frac{18-b^2}{2b}$

Volume of box, V= $b^2h$

Substitute the values

$V=b^2\times \frac{18-b^2}{2b}$

$V=\frac{1}{2}(18b-b^3)$

Differentiate w. r.t b

$\frac{dV}{db}=\frac{1}{2}(18-3b^2)$

$\frac{dV}{db}=0$

$\frac{1}{2}(18-3b^2)=0$

$\implies 18-3b^2=0$

$\implies 3b^2=18$

$b^2=6$

$b=\pm \sqrt{6}$

$b=\sqrt{6}$

The negative value of b is not possible because length cannot be negative.

Again differentiate w.r.t b

$\frac{d^2V}{db^2}=-3b$

At $b=\sqrt{6}$

$\frac{d^2V}{db^2}=-3\sqrt{6}$

Hence, the volume of box is maximum at $b=\sqrt{6}$ .

$h=\frac{18-(\sqrt{6})^2}{2\sqrt{6}}$

$h=\frac{18-6}{2\sqrt{6}}$

$h=\frac{12}{2\sqrt{6}}$

$h=\sqrt{6}$

$b=h=\sqrt{6}$ m

7 0

3 years ago

Please help!............

atroni [7]

The answer for your question is B. 5

7 0

3 years ago