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Vanyuwa [196]
3 years ago
7

You reflect the point ( -7, -6) across

Mathematics
1 answer:
Leokris [45]3 years ago
4 0
Reflecting is pushing it across from one side to another.
The answer would be (7,6)
Sorry I'm late.
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I need y’all to help me asap!!!!!!
timofeeve [1]

Answer:

-1

Step-by-step explanation:

f(0) = -5^0 = -1

8 0
3 years ago
209 divided by 3 estimate
SpyIntel [72]

Answer:

The quotient is estimated to be 69.

Other:

Brainliest? Thanks!

7 0
3 years ago
Read 2 more answers
Find m<DCV and m<VBD​
max2010maxim [7]

9514 1404 393

Answer:

  • m∠DCV = 50°
  • m∠VBD = 50°

Step-by-step explanation:

Arc DV is 100°, so any inscribed angle that intercepts that arc will have a measure that is half of 100°, or 50°.

Inscribed angles DCV and VBD both intercept arc DV, so both are 50°.

5 0
2 years ago
insurance company checks police records on 559 accidents selected at random and notes that teenagers were at the wheel in 91 of
ss7ja [257]

Answer: (13.22\%,\ 19.34\%)

Step-by-step explanation:

Given : Sample space : n= 559

Sample proportion : \hat{p}=\dfrac{91}{559}=0.162790697674\approx0.1628

=16.28\%

Significance level : \alpha= 1-0.95=0.05

Critical value : z_{\alpha/2}=1.96

Confidence level for population proportion:-

\hat{p}\pm z_{\alpha/2}\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}\\\\=0.1628\pm (1.96)\sqrt{\dfrac{0.1628(1-0.1628)}{559}}\\\\=0.1628\pm0.030604971367\\\\\approx 0.1628\pm0.0306=(0.1322,\ 0.1934)=(13.22\%,\ 19.34\%)

Hence, 95% confidence interval for the percentage of all auto accidents that involve teenage drivers.= (13.22\%,\ 19.34\%)

7 0
3 years ago
He can run 20 km in 95 minutes. He wants to know how many kilometers he will go if he runs at the same pace for 285 minutes.
DIA [1.3K]

Answer:

60km

Step-by-step explanation:

In 95 mins,he can run is 20km

In 1 min,he can run is 20/95

= 4/19in lowest

Now,

In 285 mins,he can run is=4/19*285

=4*15 in lowest

=60 km

3 0
3 years ago
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