The graph looks like this, on the enclosed pic:
One feature is that it's periodic and torn (has cut-off points), meaning the domain is the same as in case of tan(x): x€R and x =/= π/2+πn.
The range equals the range of arcsin(x): -π/2<=y<=π/2 OR y€[-π/2;π/2]
Hope could understand and if it helped! :)
This is vague. Any dimensions that make a triangle can make more than one, just draw another right next to it. What's really being asked is which dimensions can make more than one non-congruent triangle.
<span>A. Three angles measuring 75°,45°, and 60°.
That's three angles, and 75+45+60 = 180, so it's a legit triangle. The angles don't determine the sides, so we have whole family of similar triangles with these dimensions. TRUE
<span>B. 3 sides measuring 7, 10, 12?
</span>Three sides determine the triangles size and shape uniquely; FALSE
<em>C. Three angles measuring 40</em></span><span><em>°</em></span><em>, 50°</em><span><em>, and 60°? </em>
40+50+60=150, no such triangle exists. FALSE
<em>D. 3 sides measuring 3,4,and 5</em>
Again, three sides uniquely determine a triangle's size and shape; FALSE
</span>
Answer: (2,6) ; 2sqrt10 units
Step-by-step explanation:
Lets just convert them into improper fractions.
1) 4 and 1/12 = 49/12.
1 and 3/4 = 7/4.
2) 7/4 = 21/12
3) 21/12 + 49/12 = 70/12
Back to mixed fractions!
70/12 = 5 and 10/12 = 5 and 5/6
=5 5/6
⭐ Answered by Foxzy0⭐
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There is another method if you want to know. You can simply just do 4 + 1 = 5. Then do 1/12 + 3/4 = 10/12 = 5/6. So it goes to 5 5/6. Your choice which ever you find more eas.