What do two equivalent expressions always have in common

321.5 is between ________ and ________ on the number line.

Lena [83]

321.5 is between ___321_____ and ___322_____ on the number line.

Answer

B

321 and 322

8 0

3 years ago

At Pizza Pi, 32% of the pizzas made last week had extra cheese. If 16 pizzas had extra cheese, how many pizzas in all were made

igor_vitrenko [27]

Answer:

50

Step-by-step explanation:

you need to put first the 32 on top of 100 since it always goes over 100 then you put 16 over a blank and you divide 32 by 16 which equals 2 so since you divided at the top you need to divide at the bottom so you divide 100 by 2 and you get 50 so 50 is your answer

7 0

3 years ago

Help quick which ones greater 7.133 is _______ 7.1437

KatRina [158]

Answer:

7.1437 is greater

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

Which drug can cause its user take dangerous risks while driving

bearhunter [10]

Alcohol, marijuana is the drug most often found in the blood of drivers involved in crashes.

4 0

3 years ago

Seven thousand lottery tickets are sold for $5 each. One ticket will win $2,000, two tickets will win $750 each, and five ticket

Keith_Richards [23]

Answer:

a) The distribution for the random variable X is given by:

X | -5 | 95 | 745 | 1995 |

P(X) | 6992/7000 | 5/7000 | 2/7000 | 1/7000 |

b) E(X)=-4.43. That means if we buy an individual ticket by $5 on this lottery the expected value of loss if $4.43.

c) $Sd(X)=\sqrt{Var(X)}=\sqrt{738.947}=27.184$

Step-by-step explanation:

In statistics and probability analysis, the expected value "is calculated by multiplying each of the possible outcomes by the likelihood each outcome will occur and then summing all of those values".

The variance of a random variable Var(X) is the expected value of the squared deviation from the mean of X, E(X).

And the standard deviation of a random variable X is just the square root of the variance.

Part a

The info given is:

N=7000 represent the number of tickets sold

$5 is the price for any ticket

Number of tickets with a prize of $2000 =1

Number of tickets with a prize of $750=2

Number of tickets with a prize of $100=5

Let X represent the random variable net gain when we buy an individual ticket. The possible values that X can assume are:

___________________________

Ticket price Prize Net gain (X)

___________________________

5 2000 1995

5 750 745

5 100 95

5 0 -5

___________________________

Now we can find the probability for each value of X

P(X=1995)=1/7000, since we ave just one prize of $2000

P(X=745)=2/7000, since we have two prizes of $750

P(X=95)=5/7000, since we have 5 prizes of $100

P(X=-5)=6992/7000. since we have 6992 prizes of $0.

So then the random variable is given by this table

X | -5 | 95 | 745 | 1995 |

P(X) | 6992/7000 | 5/7000 | 2/7000 | 1/7000 |

Part b

In order to calculate the expected value we can use the following formula:

$E(X)=\sum_{i=1}^n X_i P(X_i)$

And if we use the values obtained we got:

$E(X)=(-5)*(\frac{6992}{7000})+(95)(\frac{5}{7000})+(745)(\frac{2}{7000})+(1995)(\frac{1}{7000})=\frac{-31000}{7000}=-4.43$

That means if we buy an individual ticket by $5 on this lottery the expected value of loss if $4.43.

Part c

In order to find the standard deviation we need to find first the second moment, given by :

$E(X^2)=\sum_{i=1}^n X^2_i P(X_i)$

And using the formula we got:

$E(X^2)=(25)*(\frac{6992}{7000})+(9025)(\frac{5}{7000})+(555025)(\frac{2}{7000})+(3980025)(\frac{1}{7000})=\frac{5310000}{7000}=758.571$

Then we can find the variance with the following formula:

$Var(X)=E(X^2)-[E(X)]^2 =758.571-(-4.43)^2 =738.947$

And then the standard deviation would be given by:

$Sd(X)=\sqrt{Var(X)}=\sqrt{738.947}=27.184$

5 0

3 years ago