[A+7= 28] is the correct equation I believe, though I may be wrong.
Answer:
12 students
Step-by-step explanation:
Given

Required
Determine the number of students that eat lunch once a week
In Sets;
If out of 9, at least 7 eats one a week then
9 - 7 eats lunch once a week

<em>In other words;</em>
2 out of 9 students eat lunch once a week
Number of students in this category is then calculated as thus;




The Least Common Denomiator Is 12
Hope this helps
Answer:
A) None
Step-by-step explanation:
1)
shoudnt neccesarily be a factor of nst, for example, if s = 3, t = 4, and n = 12, then both s and t are factors of n, but
is not a factor of nst = 144.
2)
shoudnt neccesarily be a factor of nst. Let s be 4, let t be 6, and let n be 12. Then n is a factor of both s and t, but
is not a factor of nst = 12*24. In fact, it is a greater number.
3) Again, s+t isnt necessarily a factor of nst, let s be 2 and t be 3. Then both s and t are factor of n = 12. However 5 = s+t is not a factor of nst = 72.
So, neither of the three options is guaranteed to be a factor of nst. In fact, for s = 4, t = 6, and n = 12, none of the three options are valid.