2.21*10^11 in standard notation

What is the value of

vladimir1956 [14]

The answer is x = -19

Solution:

9(x + 1) = -162

Expand:

9x + 9 = -162
9x = -162 - 9
9x = -171
x = -171/9
x = -19

6 0

2 years ago

Find the first six terms of the sequence. a1 = 1, an = 4 • an-1

maksim [4K]

$\bf \begin{array}{ccllll}
n&term&value\\
---&-----&-----\\
1&a_1&1\\
2&a_2&4\cdot a_{2-1}\\
&&4\cdot a_1\\
&&4\\
3&a_3&4\cdot a_{3-1}\\
&&4\cdot a_2\\
&&16\\
4&a_4&4\cdot a_{4-1}\\
&&4\cdot a_3\\
&&64\\
5&a_5&4\cdot a_{5-1}\\
&&4\cdot a_4\\
&&256\\
6&a_6&4\cdot a_{6-1}\\
&&4\cdot a_5\\
&&1024
\end{array}$

3 0

3 years ago

What is the constant term in (2x+9)(x-4)(x+5)

andrezito [222]

Answer:

$-180$

Step-by-step explanation:

$\left(2x+9\right)\left(x-4\right)\left(x+5\right)$

$\left(2x^2+x-36\right)\left(x+5\right)$

$2x^3+11x^2-31x-180$

6 0

3 years ago

Read 2 more answers

The equation y = \large 1\frac{1}{2}x represents the number of cups of dried fruit, y, needed to make x pounds of granola. Deter

Natasha2012 [34]

Answer:

$(1\frac{1}{2},1)$ - False

$(4,6)$ - True

$(18,12)$ -- False

$(0,0)$ -- True

$(2\frac{1}{2},3\frac{3}{4})$ -- True

Step-by-step explanation:

The points are

$(1\frac{1}{2},1)$ , $(4,6)$ , $(18,12)$ , $(0,0)$ and $(2\frac{1}{2},3\frac{3}{4})$ ---- missing from the question

Given

$y = 1\frac{1}{2}x$

Required

Determine if each of the points would be on $y = 1\frac{1}{2}x$

To do this, we simply substitute the value of x and of each point in $y = 1\frac{1}{2}x$ .

(a) $(1\frac{1}{2},1)$

In this case;

$x = 1\frac{1}{2}$ and $y = 1$

$y = 1\frac{1}{2}x$ becomes

$y = 1\frac{1}{2} * 1\frac{1}{2}$

$y = \frac{3}{2} * \frac{3}{2}$

$y = \frac{9}{4}$

$y = 2\frac{1}{4}$

The point $(1\frac{1}{2},1)$ won't be on the graph because the corresponding value of y for $x = 1\frac{1}{2}$ is $y = 2\frac{1}{4}$

(b) $(4,6)$

In this case;

$x = 4$

$y = 6$

$y = 1\frac{1}{2}x$ becomes

$y = 1\frac{1}{2} * 4$

$y = \frac{3}{2} * 4$

$y = \frac{3* 4}{2}$

$y = \frac{12}{2}$

$y = 6$

The point $(4,6)$ would be on the graph because the corresponding value of y for $x = 4$ is $y = 6$

(c) $(18,12)$

In this case:

$x = 18;y = 12$

$y = 1\frac{1}{2}x$ becomes

$y = 1\frac{1}{2} * 18$

$y = \frac{3}{2} * 18$

$y = \frac{3* 18}{2}$

$y = \frac{54}{2}$

$y = 27$

The point $(18,12)$ wouldn't be on the graph because the corresponding value of y for $x = 18$ is $y = 12$

(d) $(0,0)$

In this case;

$x =0; y = 0$

$y = 1\frac{1}{2}x$ becomes

$y = 1\frac{1}{2} * 0$

$y = 0$

The point $(0,0)$ would be on the graph because the corresponding value of y for $x = 0$ is $y = 0$

(e) $(2\frac{1}{2},3\frac{3}{4})$

In this case:

$x = 2\frac{1}{2}$ ; $y = 3\frac{3}{4}$

$y = 1\frac{1}{2}x$ becomes

$y = 1\frac{1}{2} * 2\frac{1}{2}$

$y = \frac{3}{2} * \frac{5}{2}$

$y = \frac{15}{4}$

$y = 3\frac{3}{4}$

The point $(2\frac{1}{2},3\frac{3}{4})$ would be on the graph because the corresponding value of y for $x = 2\frac{1}{2}$ is $y = 3\frac{3}{4}$

3 0

3 years ago

Can someone please help me with this problem? You need to find the value of x and y by using the strategy of ELIMINATION. Please

Setler [38]

Answer:

x = 136/35; y = -⁹/₁₀

Step-by-step explanation:

(1) 7x + 8y = 20

(2) 7x – 2y = 29 Subtract (2) from (1)

10y = -9 Divide each side by 10

(3) y = -⁹/₁₀ Substitute (3) into (1)

7x - 2(-⁹/₁₀) = 29

7x + 18/10 = 29 Subtract 18/10 from each side

7x = 29 - 18/10

7x = (290 - 18)/10

7x = 272/10 Divide each side by 7

x = 272/70

x = 136/35

x = 136/35; y = -⁹/₁₀

Check:

(1) 7(136/35) + 8(-⁹/₁₀) = 20

136/5 - 72/10 = 20

136/5 - 36/5 = 20

100/5 = 20

20 = 20

(2) 7(136/35) – 2(-⁹/₁₀) = 29

136/5 + 18/10 = 29

136/5 + ⁹/₅ = 29

145/5 = 29

29 = 29

5 0

3 years ago