Answer:
0.903264
Step-by-step explanation:
Given that a TV set contains five circuit boards of type A, five of type B, and four of type C. The probability of failing in its first 5000 hours of use is 0.03 for a type A circuit board, 0.04 for a type B circuit board, and 0.03 for a type C circuit board.
Let A' = the event that A fails, B' = B fails and C'= C fails.
Probability that no circuit board fails = Prob (A'B'C')
= P(A')P(B')P(C') (since A,B, C are independent, their complements are independent
= (1-0.03)(1-0.04)(1-0.03)
= 0.903264
Answer:
80, 20 suvs in 45 vehicles, 45 is 1/4 of 180, so just multiply 20 times 4 and the answer you get is 80
Answer:
option b
Step-by-step explanation:
the denominator is in the surd form, so it must be rationalized
Answer:
a
Step-by-step explanation:
ssdsdaaaaashjkkkllbhgdsfiii
Hopes this if it doesn’t I any so sorry if I got it wrong:
Answer: 6561
