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3 years ago

13

I need help w/ these two problems if you don't mind.

2 answers:

dusya [7]3 years ago

4 0

The answers would be a and then ctell me if you need an explaination

Anarel [89]3 years ago

3 0

On a line graph, closed circles denote an endpoint of a graph where the point belongs to the set. An open circle denotes an endpoint where the final point isn’t a part of the set. Think of it like avoiding the very last point in the set, so that it isn’t equal to it.

20 is anything above negative six, where negative six isn’t a part of the set because of the open circle (A).

21 is numbers between negative four and five, where the two endpoints don’t belong to the set because of the open circles (C).

Hope this helps!

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I need the answer fore both plsss

grandymaker [24]

Answer: 6i) 6a² - 2ab

6ii) -2b³

6iii) b³ + 7b² - 49b

<u>Step-by-step explanation:</u>

6i) (a + b)(5a - 3b) + (a - 3b)(a - b)

= 5a² - 3ab + 5ab - 3b² + a² - ab - 3ab + 3b²

= 5a² + 2ab - 3b² + a² - 4ab + 3b²

= 6a² - 2ab

6ii) (a - b)(a² + b² + ab) - (a + b)(a² + b² - ab)

= a³ + ab² + a²b - ab² - a²b - b³ - (a³ + ab² - a²b -ab² + a²b + b³)

= a³ - b³ - (a³ + b³)

= a³ - b³ - a³ - b³

= -2b³

6iii) (b² - 49)(b + 7) + 343

= b³ + 7b² - 49b - 343 + 343

= b³ + 7b² - 49b

You are allowed a maximum of 3 questions.

Please post #7 on a different question.

5 0

3 years ago

Write a linear function f with the values f (3)=-1 and f (6)=1

MArishka [77]

Answer:

f(x)= $\frac{2}{3}$ x-3

Hope this helps ;)

5 0

3 years ago

A 12 ft. ladder is leaning against a house. The ladder makes a 60° angle with the ground. Use special right triangles to find ho

OlgaM077 [116]

Given:

The length of the ladder = 12 ft

The angle of ladder with ground = 60 degrees

To find:

How far up the building the ladder will reach.

Solution:

Using the given information draw a figure as shown below.

We need to find the vertical distance between the top of ladder and the ground.

Let x be the required distance.

In a right angle triangle,

$\sin \theta=\dfrac{Perpendicular}{Hypotenuse}$

In the below triangle ABC,

$\sin A=\dfrac{BC}{AC}$

$\sin 60^\circ=\dfrac{x}{12}$

$\dfrac{\sqrt{3}}{2}=\dfrac{x}{12}$

Multiply both sides by 12.

$\dfrac{\sqrt{3}}{2}\times 12=x$

$6\sqrt{3}=x$

Therefore, the ladder will reach $6\sqrt{3}$ ft far up the building.

4 0

3 years ago

Help? Sorry ik how “Simple” this is to others but I never understood.

Artist 52 [7]

Since there are 100 squares and 6 aren’t colored in, the answer should be .94. It’s kind of like counting a dollar since 100 pennies = a dollar.

5 0

3 years ago

Does 8/18 terminates or repeats

sammy [17]

It terminates your welcome

4 0

3 years ago