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Aleksandr-060686 [28]
3 years ago
12

Find each of the following using prime

Mathematics
2 answers:
katen-ka-za [31]3 years ago
7 0

Answer:

15

Step-by-step explanation:

The product of the prime factors of 3375 are

3375 = 3³ × 5³, then

\sqrt[3]{3375}

= \sqrt[3]{3^3(5^3)}

= \sqrt[3]{3^3} × \sqrt[3]{5^3}

= 3 × 5

= 15

gavmur [86]3 years ago
4 0
The answer would be 15
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3 years ago
Name Date 34bral Kuta Software - Infinite Algebra 2 Solving Absolute Value Equations Solve each equation. 1) 13x1=9 2) 1-3r1=9 R
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-5|3+4k|=-115

start by dividing both sided by -5

\frac{-5}{-5}|3+4k|=-\frac{115}{-5}|3+4k|=23

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\begin{gathered} 3+4k=23 \\ -(3+4k)=23 \end{gathered}

solve each of them

\begin{gathered} 3+4k=23 \\ 4k=23-3 \\ 4k=20 \\ k=\frac{20}{4}=5 \end{gathered}

for the second equation

\begin{gathered} -(3+4k)=23 \\ -3-4k=23 \\ -4k=23+3 \\ -4k=26 \\ k=-\frac{26}{4}=-6.5 \end{gathered}

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1 year ago
George jogged a total distance of 9 and 1 over 2 miles during the months of October and November. If George only jogged 1 over 4
kipiarov [429]
I believe what you are looking for is... 9.5/.2= 47.5
8 0
3 years ago
Read 2 more answers
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