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2 years ago

WILL GIVE BRAINLIEST

Mathematics

2 answers:

mash [69]2 years ago

6 0

Answer:

(16,-1)

Step-by-step explanation:

Novay_Z [31]2 years ago

5 0

Answer:

$x \: midpoint = \frac{x1 + x2}{2}$

$y \: midpoint = \frac{y1 + y2}{2}$

subs points into formula:

$x = \frac{32 + 0}{2} = 16 \\ y = \frac{ - 1 + ( -12 )}{2} = \frac{ - 13}{2}$

midpoint is:

$(16, \frac{ - 13}{2} )$

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A college conducts a common test for all the students. For the Mathematics portion of this test, the scores are normally distrib

Jet001 [13]

Using the normal distribution, it is found that 58.97% of students would be expected to score between 400 and 590.

<h3>Normal Probability Distribution</h3>

The z-score of a measure X of a normally distributed variable with mean $\mu$ and standard deviation $\sigma$ is given by:

$Z = \frac{X - \mu}{\sigma}$

The z-score measures how many standard deviations the measure is above or below the mean.

Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.

The mean and the standard deviation are given, respectively, by:

$\mu = 502, \sigma = 115$

The proportion of students between 400 and 590 is the <u>p-value of Z when X = 590 subtracted by the p-value of Z when X = 400</u>, hence:

X = 590:

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{590 - 502}{115}$

Z = 0.76

Z = 0.76 has a p-value of 0.7764.

X = 400:

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{400 - 502}{115}$

Z = -0.89

Z = -0.89 has a p-value of 0.1867.

0.7764 - 0.1867 = 0.5897 = 58.97%.

58.97% of students would be expected to score between 400 and 590.

More can be learned about the normal distribution at brainly.com/question/27643290

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2 years ago

I need assistance solving these questions using Cramers' Rule (which I am frankly terrible at) and need these to finish my homew

Scrat [10]

Answer:

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3 years ago

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NeX [460]

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3 years ago

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sineoko [7]

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3 years ago

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Len [333]

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3 years ago

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