Answer:
B. No Solution
Step-by-step explanation:
First, you'll want to distribute 3 through the parentheses (in other words, multiple the parentheses).
Next, you collect the like terms, in this case, the like terms are -3n and 5n.
Finally, you will cancel equal terms on both sides of the equation (which is the 2n).
This makes the statement false for any value of n. Meaning that your answer is B, no solution.
Answer:
The amount of heat required to raise the temperature of liquid water is 9605 kilo joule .
Step-by-step explanation:
Given as :
The mass of liquid water = 50 g
The initial temperature = = 15°c
The final temperature = = 100°c
The latent heat of vaporization of water = 2260.0 J/g
Let The amount of heat required to raise temperature = Q Joule
Now, From method
Heat = mass × latent heat × change in temperature
Or, Q = m × s × ΔT
or, Q = m × s × ( -
)
So, Q = 50 g × 2260.0 J/g × ( 100°c - 15°c )
Or, Q = 50 g × 2260.0 J/g × 85°c
∴ Q = 9,605,000 joule
Or, Q = 9,605 × 10³ joule
Or, Q = 9605 kilo joule
Hence The amount of heat required to raise the temperature of liquid water is 9605 kilo joule . Answer
Answer:
0.273 = 27.3% probability that she was late on Thursday.
Step-by-step explanation:
On time on Monday, late on Thursday:
Possible outcomes (tuesday-wednesday-thursday).
on time(0.7 probability) - on time(0.7 probability) - late(0.3 probability)
on time(0.7 probability) - late(0.3 probability) - late(0.2 probability)
late(0.3 probability) - on time(0.8 probability) - late(0.3 probability)
late(0.3 probability) - late(0.2 probability) - late(0.2 probability).
What is the probability she was late on Thursday?
Sum of these four outcomes. So
0.273 = 27.3% probability that she was late on Thursday.