3(-n+4)+5n=2n a. n=3 b. no solution c. infinitely many solutions
2 answers:
Answer:
B. No Solution
Step-by-step explanation:
First, you'll want to distribute 3 through the parentheses (in other words, multiple the parentheses).
Next, you collect the like terms, in this case, the like terms are -3n and 5n.
Finally, you will cancel equal terms on both sides of the equation (which is the 2n).
This makes the statement false for any value of n. Meaning that your answer is B, no solution.
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Explanation:
In order to prove that affirmation, we define the function g over the interval [0, 1/2] with the formula
If we evaluate g at the endpoints we have
g(0) = f(1/2)-f(0) = f(1/2) - f(1) (because f(0) = f(1))
g(1/2) = f(1) - f(1/2) = -g(0)
Since g(1/2) = -g(0), we have one chance out of three
- g(0) > 0 and g(1/2) < 0
- g(0) < 0 and g(1/2) > 0
- g(0) = g(1/2) = 0
We will prove that g has a zero on [0,1/2]. If g(0) = 0, then it is trivial. If g(0) ≠ 0, then we are in one of the first two cases, and therefore g(0) * g(1/2) < 0. Since f is continuous, so is g. Bolzano's Theorem assures that there exists c in (0,1/2) such that g(c) = 0. This proves that g has at least one zero on [0,1/2].
Let c be a 0 of g, then we have
Hence, f(c+1/2) = f(c) as we wanted.