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3 years ago

10

Find the value of Log2 32=y

1 answer:

lukranit [14]3 years ago

3 0

Answer:

y=5

Step-by-step explanation:

We are solving

$log_232=y$

The logarithm is basically asking us this question:

$2^y=32$

Or what power should I raise 2 to so that it will give me 32?

We know that $2^5=32$

Therefore $y=5$ .

<em>P.S: calculating logarithms is not an algorithmic process: you have to rely mostly on educated guesses to get your answers.</em>

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Read 2 more answers

What is the equation for

WARRIOR [948]

The equation of a line that is perpendicular to the given line is y = –4x – 16.

Solution:

The equation of a line given is y = 0.25x – 7

Slope of the given line( $m_1$ ) = 0.25

Let $m_2$ be the slope of the perpendicular line.

Passes through the point (–6, 8).

<em>If two lines are perpendicular then the product of the slopes equal to –1.</em>

$\Rightarrow m_1 \cdot m_2=-1$

$\Rightarrow 0.25\cdot m_2=-1$

$\Rightarrow m_2=\frac{-1}{0.25}$

$\Rightarrow m_2=-4$

Point-slope intercept formula:

$y-y_1=m(x-x_1)$

$x_1=-6, y_1=8$ and $m=-4$

Substitute these in the formula, we get

$y-8=-4(x-(-6))$

$y-8=-4(x+6)$

$y-8=-4x-24$

Add 8 on both sides of the equation.

$y-8+8=-4x-24+8$

$y=-4x-16$

Hence the equation of a line that is perpendicular to the given line is

y = –4x – 16

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3 years ago