Question

Find the value of Log2 32=y

Answer 1

Answer:

y=5

Step-by-step explanation:

We are solving

$log_232=y$

The logarithm is basically asking us this question:

$2^y=32$

Or what power should I raise 2 to so that it will give me 32?

We know that $2^5=32$

Therefore $y=5$.

P.S: calculating logarithms is not an algorithmic process: you have to rely mostly on educated guesses to get your  answers.