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cupoosta [38]
3 years ago
8

Write the triangle congruence statement and the congruence theorem that proves the triangles congruent. If the triangles are bot

h congruent, write n/a in the congruence statement and select not congruent for the theorem.
Can anyone please help?! I’ll give brainliest !!

Mathematics
2 answers:
nadezda [96]3 years ago
8 0

Answer:

SSS

Step-by-step explanation:

Juli2301 [7.4K]3 years ago
5 0

Answer:

WZY congruent to WXY

Step-by-step explanation:

by SSS theorem

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Ricky is on a bicycle trip.every 4 days he bikes 230km. If Rick keeps his same pace for 16 days how many kilometers will he bike
Arlecino [84]
He will bike 920 km because 4 days time 4 equals 16 days and 230 km times 4 equals 920 km.
plz give mw brainliest if this helped
3 0
3 years ago
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The product of two consecutive odd integers is 72. Write a quadratic equation to find the integers,
zimovet [89]

<u>Answer:</u>

x^2 + x - 72 = 0

<u>Explanation:</u>

We are given product of two consecutive odd integers is equal to 72.

Let one integer be x , then since these are consecutive and odd so the other integer will be equal to x + 1.  

Their product is equal to 72. So,

x * (x + 1) = 72

=> x^2 + x = 72

=>  x^2 + x - 72 = 0 is the required quadratic equation.

5 0
3 years ago
What is the answer someone help please
Maru [420]
166.25 thats the answer
4 0
3 years ago
<img src="https://tex.z-dn.net/?f=%28x%5E%7B2%7D%20%2Bx-3%29%3A%20%28x%5E%7B2%7D%20-4%29%5Cgeq%201" id="TexFormula1" title="(x^{
Jlenok [28]

Answer:

x>2

Step-by-step explanation:

When given the following inequality;

(x^2+x-3):(x^2-4)\geq1

Rewrite in a fractional form so that it is easier to work with. Remember, a ratio is another way of expressing a fraction where the first term is the numerator (value over the fraction) and the second is the denominator(value under the fraction);

\frac{x^2+x-3}{x^2-4}\geq1

Now bring all of the terms to one side so that the other side is just a zero, use the idea of inverse operations to achieve this:

\frac{x^2+x-3}{x^2-4}-1\geq0

Convert the (1) to have the like denominator as the other term on the left side. Keep in mind, any term over itself is equal to (1);

\frac{x^2+x-3}{x^2-4}-\frac{x^2-4}{x^2-4}\geq0

Perform the operation on the other side distribute the negative sign and combine like terms;

\frac{(x^2+x-3)-(x^2-4)}{x^2-4}\geq0\\\\\frac{x^2+x-3-x^2+4}{x^2-4}\geq0\\\\\frac{x+1}{x^2-4}\geq0

Factor the equation so that one can find the intervales where the inequality is true;

\frac{x+1}{(x-2)(x+2)}\geq0

Solve to find the intervales when the equation is true. These intervales are the spaces between the zeros. The zeros of the inequality can be found using the zero product property (which states that any number times zero equals zero), these zeros are as follows;

-1, 2, -2

Therefore the intervales are the following, remember, the denominator cannot be zero, therefore some zeros are not included in the domain

x\leq-2\\-2

Substitute a value in these intervales to find out if the inequality is positive or negative, if it is positive then the interval is a solution, if it is negative then it is not a solution. This is because the inequality is greater than or equal to zero;

x\leq-2   -> negative

-2   -> neagtive

-1\leq x   -> neagtive

x>2   -> positive

Therefore, the solution to the inequality is the following;

x>2

6 0
3 years ago
Help please helpp ohh god
gtnhenbr [62]
i feel your pain though :/
8 0
3 years ago
Read 2 more answers
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