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3 years ago

Fernanda's expenditures for this month are: rent, $750.00; groceries, $346.00;

Mathematics

2 answers:

Ivahew [28]3 years ago

7 0

The answer is 1719.09 because that’s the total

dezoksy [38]3 years ago

3 0

Answer:

she spent $1719.09 this month

Step-by-step explanation:

To answer this, you simply have to add up all the amounts:

750.00 + 346.00 = 1096.00

1096 + 205.49 = 1301.49

1301.49 + 168.41 = 1469.9

1469.9 + 67.59 = 1537.49

1537.49 + 50.00 = 1587.49

1587.49 + 131.60 = 1719.09

So, she spent $1719.09 this month

Hope this helps :)

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HACTEHA [7]

Answer:

Required equation of tangent plane is $z=\frac{6}{5}(x-5y-11)$ .

Step-by-step explanation:

Given surface function is,

$f(x,y)=6-\frac{6}{5}(x-y)$

To find tangent plane at the point (5,-1,1).

We know equation of tangent plane at the point $(x_0,y_0,z_0)[/tex] is,

$z=f(x_0,y_0)+f_x(x_0,y_0)(x-x_0)+f_y(x_0,y_0)(y-y_0)\hfill (1)$

So that,

$f(x_0,y_0)=6-\frac{6}{5}(5+1)=-\frac{6}{5}$

$f_x=-\frac{6}{5}y\implies f_x(5,-1,1)=\frac{6}{5}$

$f_y=-\frac{6}{5}x\implies f_y(5,-1,1)=-6$

Substitute all these values in (1) we get,

$z=\frac{6}{5}(x-5)-6(y+1)-\frac{6}{5}$

$\therefore z=\frac{6}{5}(x-5y-11)$

Which is the required euation of tangent plane.

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3 years ago

Twenty-four is ___% of 80

Ugo [173]

Answer:

Step-by-step explanation:

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olganol [36]

Answer:

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Step-by-step explanation:

substitute values we have into the formula:

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Marizza181 [45]

Answer:

The probability that the result is positive is P=0.04475=4.475%.

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We have the events:

D: disease present

ND: disease not present

P: test positive

F: test false

Then, the information we have is:

P(D)=0.005

P(P | D)=0.99

P(P | ND)=0.04

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$P(P)=P(P | D)*P(D)+P(P | ND)*(1-P(D))\\\\P(P)=0.99*0.005+0.04*0.995\\\\P(P)=0.00495+0.0398=0.04475$

The probability that the result is positive is P=0.04475.

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4 years ago

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3 years ago