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blsea [12.9K]
3 years ago
12

A meter stick whose mass is 310 grams lies on ice. You pull at one end of the meter stick, at right angles to the stick, with a

force F = 9 newtons. The ensuing motion of the meter stick is quite complicated, but what are the initial magnitude and direction of the rate of change of the momentum of the stick, dPtot/dt, when you first apply the force?
Physics
1 answer:
Travka [436]3 years ago
8 0

Answer:

\frac{dp}{dt} = 9N and the direction of change of momentum will be in the direction of the applied force.

Explanation:

Given data in the question:

mass of the meter stick, ma = 310 grams

Applied force on the stick, F = 9 Newtons

Now, from the Newton's second law of motion we have

Net force = change in momentum per unit change in time

or

F=\frac{dp}{dt}

or

\frac{dp}{dt} = 9N

and the direction of change of momentum will be in the direction of the applied force.

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Answer:

acidic

Explanation:

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Bogdan [553]

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A student used a yardstick to model the displacement of rock at a fault during an earthquake. The student bent the yardstick wit
jonny [76]
I think the correct answer would be B. The process of elastic rebound is being shown by the student. It is a theory that is used to explain earthquakes. It focuses on how energy is being spread in times of earthquakes. As the rocks on the fault experiences shift and force, these rocks would be accumulating energy causing it to deform reaching the internal strength and eventually exceeding it. At that moment, a rapid motion would happen along the fault, which releases the energy, then the rocks would go back to its original shape or the undeformed state. This theory is the first theory that sufficiently was able to explain earthquakes.
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3 years ago
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A 0.274 kg block is pushed up a frictionless ramp inclined at angle of 32° above the horizon. The push force is a constant 2.55
SpyIntel [72]

Answer:

The answer is 2,416 m/s. Let's jump in.

Explanation:

We do work with the amount of energy we can transfer to objects. According to energy theory:

W = ΔE

Also as we know W = F.x

We choose our reference point as a horizontal line at the block's rest point.<u> At the rest, block doesn't have kinetic energy</u> and <u>since it is on the reference point(as we decided) it also has no potential energy.</u>

Under the force block gains;

W = F.x → W=2,55.0,71=1,8105\frac{N}{m}

In the second position block has both kinetic and potential energy. Following the law of conservation of energy;

W = ΔE = Kinetic energy + Potantial Energy

W = ΔE = \frac{1}{2} mV^{2} + mgh

Here we can find h in the triangle i draw in the picture using sine theorem;

In a triangle \frac{a}{sinA}=\frac{b}{sinB}=\frac{c}{sinC}

In our situation

\frac{0,71}{sin90} =\frac{h}{sin32} → h=0,376

Therefore

1,8105=\frac{1}{2} 0,274V^{2} +0,274.9,81.0,376

→ V=2,416

7 0
3 years ago
1. Which statement about friction is true?(1 point) A. Static friction and kinetic friction in a system always act in the same d
ArbitrLikvidat [17]

Answer:

true 1Ay 2D

Explanation:

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A) True. The friction force opposes the movement caused by the external force,

B) False. Mantuano in the opposite direction force

C) False. The static and scientific friction force act in the same direction, since the second appears when the movement does not start and the static friction decreases.

D) Fale the static and kinetic friction forces act in the same direction

2) How to overcome friction on a ramp

A) False. If the texture of the surface becomes rough, the friction force increases

B) False. Pressing the brick against the surface increases the normal and as the friction is proportional to the normal, it also increases

C) False. By lowering the table the weight component in the friction direction decreases

D) True. When lifting the board, the weight component increases and therefore can become greater than the friction

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           W sin tea - my mg cos tea = m a

As it increases, the sine increases and the cosine decreases.

3 0
3 years ago
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