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blsea [12.9K]
3 years ago
12

A meter stick whose mass is 310 grams lies on ice. You pull at one end of the meter stick, at right angles to the stick, with a

force F = 9 newtons. The ensuing motion of the meter stick is quite complicated, but what are the initial magnitude and direction of the rate of change of the momentum of the stick, dPtot/dt, when you first apply the force?
Physics
1 answer:
Travka [436]3 years ago
8 0

Answer:

\frac{dp}{dt} = 9N and the direction of change of momentum will be in the direction of the applied force.

Explanation:

Given data in the question:

mass of the meter stick, ma = 310 grams

Applied force on the stick, F = 9 Newtons

Now, from the Newton's second law of motion we have

Net force = change in momentum per unit change in time

or

F=\frac{dp}{dt}

or

\frac{dp}{dt} = 9N

and the direction of change of momentum will be in the direction of the applied force.

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3 years ago
A culture is a group of people that share the same __________.
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Read 2 more answers
The stoplight had just changed and a 2100 kg Cadillac had entered the intersection, heading north at 3.2 m/s , when it was struc
elena55 [62]

Explanation:

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Mass of Volkswagen, m_2=1100\ kg

The cars stuck together and slid to a halt, leaving skid marks angled 35 degrees north of east.

According to the law of conservation of momentum,

The momentum along x axis, m_1v_1=(m_1+m_2)\ usin35............(1)

The momentum along y axis, m_2v_2=(m_1+m_2)\ ucos35...........(2)

From equation (1) and (2) it is clear that,

\dfrac{m_1v_1}{m_2v_2}=tan35

v_2=\dfrac{m_1v_1}{m_2\ tan35}

v_2=\dfrac{2100\times 3.2}{1100\times \ tan35}

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6 0
3 years ago
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Korvikt [17]

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6 0
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