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Greeley [361]
3 years ago
5

A 1.10-kg wrench is acting on a nut trying to turn it. The length of the wrench lies directly to the east of the nut. A force 15

0.0 N acts on the wrench at a position 15.0 cm from the center of the nut in a direction 30.0° north of east. What is the magnitude of the torque about the center of the nut
Physics
1 answer:
gtnhenbr [62]3 years ago
7 0

Answer:

τ = 11.25 Nm

Explanation:

Given,

Mass of wrench, m = 1.10 Kg

Force on the wrench, F = 150 N

position of force, r = 15 cm = 0.15 m

angle of nut = 30°

We know,

torque = Force x distance

F = 150 sin 30°

F = 75 N

τ = 75 x r

τ = 75 x 0.15

τ = 11.25 Nm

Torque at the center of the nut is equal to 11.25 N.

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What are the two ways to change the frictional force between two solid surfaces
Jet001 [13]

Explanation:

I think The strength of the force of friction depends on two factors: <em><u>how hard the surfaces push together</u></em> and <em><u>the types of surfaces involved</u></em><em><u>.</u></em><em><u> </u></em>

Tell me if it's correct.

3 0
3 years ago
What hanging mass will stretch a 3.0-m-long, 0.32 mm - diameter steel wire by 1.3 mm ? The Young's modulus of steel is 20×10^10
raketka [301]

Answer:

0.71 kg

Explanation:

L = length of the steel wire = 3.0 m

d = diameter of steel wire = 0.32 mm = 0.32 x 10⁻³ m

Area of cross-section of the steel wire is given as

A = (0.25) πd²

A = (0.25) (3.14) (0.32 x 10⁻³)²

A = 8.04 x 10⁻⁸ m²

ΔL = change in length of the wire = 1.3 mm = 1.3 x 10⁻³ m

Y = Young's modulus of steel = 20 x 10¹⁰ Nm⁻²

m = mass hanging

F = weight of the mass hanging

Young's modulus of steel is given as

Y = \frac{FL}{A\Delta L}

20\times 10^{10} = \frac{F(3)}{(8.04\times 10^{-8})(1.3\times 10^{-3})}

F = 6.968 N

Weight of the hanging mass is given as

F = mg

6.968 = m (9.8)

m = 0.71 kg

7 0
4 years ago
Looking at the velocity vs time graph, between points b and c on the graph, the object was
mihalych1998 [28]
Between B and C, the object was going at a constant velocity; it is going 60 m/min consistently for that time frame.
8 0
3 years ago
Please help me on my physics hw ​
MatroZZZ [7]

Answer:

1. 11 A

2. 240 V

3. 8 Ω

4. 60 C

5. 14400 C

Explanation:

1. Determination of the current.

Voltage (V) = 110 V

Resistance (R) = 10 Ω

Current (I) =?

V = IR

110 = I × 10

Divide both side by 10

I = 110 / 10

I = 11 A

2. Determination of the voltage

Current (I) = 3 A

Resistance (R) = 80 Ω

Voltage (V) =?

V = IR

V = 3 × 80

V = 240 V

3. Determination of the resistance.

Current (I) = 0.5 A

Voltage (V) = 4 V

Resistance (R) =?

V = IR

4 = 0.5 × R

Divide both side by 0.5

R = 4 / 0.5

R = 8 Ω

4. Determination of the charge

Current (I) = 2 A

Time (t) = 30 s

Charge (Q) =?

Q = it

Q = 2 × 30

Q = 60 C

5. Determination of the charge.

We'll begin by converting 20 mins to seconds. This can be obtained as follow:

1 min = 60 s

Therefore,

20 mins = 20 × 60

20 mins = 1200 s

Finally, we shall determine the charge as follow:

Current (I) = 12 A

Time (t) = 1200 s

Charge (Q) =?

Q = it

Q = 12 × 1200

Q = 14400 C

6 0
3 years ago
(Fiqure 1) shows the velocity-versus-time graphs for two objects A and B the motion of the ohiecds Zach savs The aranh could rep
olchik [2.2K]

Answer:

a.neither of them is correct

b. Zach's statement is not correct, since do not know where the objects started and can't be sure if they pass each other.

c. Victoria's statement is not correct as the objects have the opposite accelerations, however free-falling objects should have the same downward acceleration

Explanation:

Fiqure 1) shows the velocity-versus-time graphs for two objects A and B the motion of the ohiecds Zach savs The aranh could represent two cars Zach traveling in opposite directions that pass each other." Victoria says, "No, I think they could be R cally from a bridge, rock A is thrown upward Victoria downward

ans :neither of them is correct

Previous Answers Submit VCorrect Figure 1 of 1

Part B V,

Why is Zach's statement wrong? Check all that apply

. A Zach's statement is not correct, since the objects move in the same direction for some time interval.

Ans: Zach's statement is not correct, since do not know where the objects started and can't be sure if they pass each other.

Previous Answers Request Answer Submit x Incorrect;

Try Again

Part C

Why is Victoria's statement wrong? Check all that apply Victoria's statement is not correct as the objects both should have been thrown either upward or downward

Answer:. Victoria's statement is not correct as the objects have the opposite accelerations, however free-falling objects should have the same downward acceleration gGraph

My explanation further from the graph will be that there are opposite bodies, one is accelerating with time , why the other is decelerating with time.

6 0
4 years ago
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