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timurjin [86]
3 years ago
14

Sometimes you wish you could go back in time and fix your mistakes but you can’t you can say sorry but it’s never enough what mo

re do they want what is a true friend it’s someone who pulls you away when something isn’t right someone who cares about you and will go out of there way to help you but I guess that dosent mattter bc apparently I’m a fake friend goodbye forever
Physics
2 answers:
Simora [160]3 years ago
7 0

(their* not there)

But- WHOAH- You don't need to say "Goodbye forever" you could find new friends who love and support you. People say things, they do things, but they're still human, just like you are. Mistakes will be made. You just gotta fight the bad and look for a brighter future. Not everyone or everything is gonna be sunshine and rainbows. It's gonna be bumpy and rough, you just gotta work out the kinks of it and move on.

Valentin [98]3 years ago
5 0

Answer:

very true

Explanation:

u ok?

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a 282 kg bumper car moving right at 3.50 m/s collides with a 155 kg bumper car moving 1.88 m/s left. afterwards, the 282 kg car
Vaselesa [24]

The momentum of the 155 kg car afterwards is 469.7 kg m/s to the right

Explanation:

We can solve the problem by using the law of conservation of momentum: the total momentum of the system is conserved before and after the collision, so we can write:

p_i = p_f\\m_1 u_1 + m_2 u_2 = m_1 v_1 + m_2 v_2

where:

m_1 = 282 kg is the mass of the bumper car

u_1 = 3.50 m/s is the initial velocity of the bumper car (we take the right as positive direction)

v_1 = 0.800 m/s is the final velocity of the bumper car

m_2 = 155 kg is the mass of the second bumper car

u_2 = -1.88 m/s is the initial velocity of the second car (moving to the left)

v_2 is the final velocity of the second car

Solving for v_2,

v_2 = \frac{m_1 u_1+m_2 u_2 - m_1 v_1}{m_2}=\frac{(282)(3.50)+(155)(-1.88)-(282)(0.800)}{155}=3.03 m/s

where the positive sign means the direction is to the right.

And now we can find the momentum of the 155 kg afterwards, which is

p_2 = m_2 v_2 = (155)(3.03)=469.7 kg m/s (to the right)

Learn more about momentum:

brainly.com/question/7973509

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brainly.com/question/2370982

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7 0
3 years ago
Where are the reproductive parts of a plant located?
Mkey [24]

Answer:

<h2>Flower </h2>

Explanation:

<h2>The flowers are the reproductive parts of a plant. Stamens are the male reproductive part and pistil is the female reproductive part.</h2><h2 />
8 0
2 years ago
Read 2 more answers
Q.4. What is the kinetic energy of a 10 kg car that is moving 4 m/s?
kodGreya [7K]

An object of mass $10 \mathrm{~kg}$ is moving with a uniform velocity of $4 \mathrm{~ms}^{-1}$. The kinetic energy possessed by the object is $80 \mathrm{~J}$.

Given:

Mass of an object $=10 \mathrm{~kg}$

Velocity $=4 \mathrm{~ms}^{-1}$

Kinetic Energy $=1 / 2 \times$ Mass of Object $\times(\text { Velocity })^{2}$

$\Rightarrow$ Kinetic Energy $=1 / 2 \times 10 \times 4 \times 4$

$\Rightarrow$Kinetic Energy $=\underline{80 \mathbf{J}}$

What is Kinetic Energy?

  • In physics, an object's kinetic energy is the energy it has as a result of its motion.
  • It is defined as the amount of work required to accelerate a body of a given mass from rest to a certain velocity.
  • The body retains its kinetic energy after gaining it during acceleration until its speed changes.
  • Kinetic energy is present in a speeding bullet, a walking human, and electromagnetic radiation such as light. The energy associated with the continual, random bouncing of atoms or molecules is another type of kinetic energy.

Learn more about kinetic energy brainly.com/question/12669551

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6 0
2 years ago
When a ball increases in speed by the same amount each second its acceleration?
MAXImum [283]
Its acceleration is constant. 
5 0
4 years ago
Between which two points of a concave mirror should an object be placed to obtain a magnificati of -3​
kobusy [5.1K]

Answer:

When object is placed between the focus (F) and pole (P) of a concave mirror, magnified and erect image of the object is formed on the back of the mirror.

When object is placed between the centre of curvature and the principal focus of a concave mirror, magnified and inverted image is formed in front of the mirror.

Explanation:

8 0
3 years ago
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