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GrogVix [38]
3 years ago
5

Sally has made a scale drawing of the airplane, in which the wingpsan is 10 inches and the tailspan is 3 inches. What is the act

ual tailspan of the airplane?
Mathematics
1 answer:
Alina [70]3 years ago
4 0
My first impulse is to say you don't provide enough info with which to solve this problem.  We need to know how many inches in the model correspond to 1 foot in the actual plane (that is, the scale factor).  What is the scale factor here?


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What is 4 to the power of x minus 3 =18
mote1985 [20]
3 to the power of 4:

=34
x
n
=
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=3⋅3⋅3⋅3
=
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⋅
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⋅
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=81
=
81

For example, 3 to the power of -4:

=3−4
x
n
=
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=134
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=13⋅3⋅3⋅3
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=181
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81

=0.012346
7 0
3 years ago
(I can mark the first correct person brainliest!)
Mashutka [201]
35 which is slope which in turn represents the speed.
6 0
3 years ago
PLEASE PLEASE HELP ME!!! Carla rode her bicycle 4 miles to the park and it took her 30 minutes.
White raven [17]

Answer:

30 mins = 0.5 hours

4.5 miles/0.5 hours = your answer

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
i have been trying to solve this compound and double angle question please help me find the answer to these question guys​
natali 33 [55]

Answer:

These type of questions are super tricky b/c you have to remember all the different versions of the identities, and then they put the question in some odd form,  I feel like this should land math professors in jail , for dishonesty , b/c it's really a form of "how tricky can I make a question and still have a way to solve it"   anyway,

Step-by-step explanation:

a)

next the question asks   1-cos 2A   and this is total abuse of notation.   the way this should be written is   1- cos( 2A)  so we know that the A is part of the cosine functions input... btw.. in any computer program,  it would never ever let you get away with that top form of the expression.  :/   anyway... I keep ranting.. huh... sorry  :P

1-cos(2A) is an odd form of the identity  1/2(1-cos(2A) = sin^{2}(A)  the 1/2 is missing but we can add that pretty easy, we just have to remember to take it out too. I usually forget to do that. and my professor marks me off completely,  totally wrong, but I just miss one small thing  :/  anyway....

our 1-cos(2A) needs the 1/2 added to it.  or if we move that 1/2 to the other side it looks like  2*sin^{2}(A)  = 1-cos(2A)  and this is that "odd" from of the identity that I was talking about.  

next let's deal with sin(2A)  it has an identity of  2 sin(A)cos(A) which is really nice for us b/c it will cancel out the 2 in then numerator for us, nice !

now our fraction looks like  [2* sin^{2}(A)] / 2 sin(A)cos(A)

so cancel out one of the sines

2*sin(A) / 2 cos(A)

cancel the 2s

Sin(A) / Cos(A) = Tan(A)

nice  it worked out  :P

b)

by the above that we just worked out, then

Tan(15) = Sin(15) / Cos(15)

I had to look up what sin of 15 is b/c it's not one of those special angles but it does have an exact form of

Sin(15) = (√3 - 1) / 2√2

Cos(A) = (√3 + 1) / 2√2

you can use rule of Cos(A-B) = Cos(A)Cos(B)+Sin(A)Sin(B) to get the above and a similar rule for Sin(A-B)

back to our problem,  the 2√2 will cancel out

then we have

Tan(15) =  (√3 - 1) /(√3 + 1)

in the form that is above that's exact, the roots could be approximated but i'll just leave that in the form that is exact.  Most math professors like that form.  

 

4 0
2 years ago
The equation of a given circle in general form is x^2+y^2-8x+12y+27=0. Write the equation in standard form, (x-h)^2+(y-k)^2=r^2,
umka2103 [35]

Answer:

(x - 4)² + (y + 6)² = 5²

Step-by-step explanation:

rearrange the general equation as follows

collect the terms in x and y together and place the constant on the right side

x² - 8x + y² + 12y = - 27

add (half the coefficient of the x/y term)² to both sides

x² + 2(- 4)x + y² + 2(6)y = - 27

(x - 4)² + 16 + (y + 6)² + 36 = - 27 + 16 + 36

(x - 4)² + (y + 6)² = 25

(x - 4)² + (y + 6)² = 5² ← in standard form



7 0
3 years ago
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