Ask question

Ask question

All categories

3 years ago

7

Arrange the absolute value expressions in increasing order of their values.

1 answer:

WARRIOR [948]3 years ago

6 0

18, 38, 43, 47, 55, 88, 90.

hope this helps!

You might be interested in

The point P on the circle x2 + y2 = r2 that is also on the terminal side of an angle θ in standard position is given. Find the i

Brut [27]

Okay so you do not really need the circle equation. if you make a triangle with it's x length as 3 and it's y length as 4, you will be able to find the third length. Do Pythagorean theorem to find the hypotenuse.
the hypotenuse will be five after you calculate it.

sin is opposite over hypotenuse or Y over R

so... the sin is 4/5

make sure you know what quadrant your triangle is in for the negatives

6 0

2 years ago

Write the following numbers in order of size start with the smallest. 0.32 0.4 0.35 0.309

fenix001 [56]

Answer:

Hey!

0.309<0.32<0.35<0.4

hope this helps you

6 0

2 years ago

Samantha is baking a cake. She needs 3/4 cup of butter for each cake. One stick of butter is 1/2 cup. How many sticks of butter

Gala2k [10]

She would need 6 sticks of butter.

6 0

3 years ago

Read 2 more answers

Use the quadratic formula to solve the equation. If necessary, round to the nearest hundredth.

likoan [24]

Answer:

Thus, the two root of the given quadratic equation $x^2+4=6x$ is 5.24 and 0.76 .

Step-by-step explanation:

Consider, the given Quadratic equation, $x^2+4=6x$

This can be written as , $x^2-6x+4=0$

We have to solve using quadratic formula,

For a given quadratic equation $ax^2+bx+c=0$ we can find roots using,

$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$ ...........(1)

Where, $\sqrt{b^2-4ac}$ is the discriminant.

Here, a = 1 , b = -6 , c = 4

Substitute in (1) , we get,

$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

$\Rightarrow x=\frac{-(-6)\pm\sqrt{(-6)^2-4\cdot 1 \cdot (4)}}{2 \cdot 1}$

$\Rightarrow x=\frac{6\pm\sqrt{20}}{2}$

$\Rightarrow x=\frac{6\pm 2\sqrt{5}}{2}$

$\Rightarrow x={3\pm \sqrt{5}}$

$\Rightarrow x_1={3+\sqrt{5}}$ and $\Rightarrow x_2={3-\sqrt{5}}$

We know $\sqrt{5}=2.23607$ (approx)

Substitute, we get,

$\Rightarrow x_1={3+2.23607}$ (approx) and $\Rightarrow x_2={3-2.23607}$ (approx)

$\Rightarrow x_1={5.23607}$ (approx) and $\Rightarrow x_2=0.76393}$ (approx)

Thus, the two root of the given quadratic equation $x^2+4=6x$ is 5.24 and 0.76 .

7 0

2 years ago

Read 2 more answers

KatRina [158]

Answer:

B (2,6,10,14)

Step-by-step explanation:

I think C and D are imposible to be the answer.

A and B are 50% to be the answer.

But I choose B.

6 0

1 year ago