Question

Given the formula for the arithmetic sequence, an = 6+ (n - 1)3, give the first 4 terms of the

Answer 1

$a(n) = 6 + 3(n - 1)$

$a(1) = 6 + 3(1 - 1)$

$a(1) = 6 + 3 \times 0$

$a(1) = 6 + 0$

$a(1) = 6$

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$a(2) = 6 + 3(2 - 1)$

$a(2) = 6 + 3 \times 1$

$a(2) = 6 + 3$

$a(2) = 9$

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$a(3) = 6 + 3(3 - 1)$

$a(3) = 6 + 3 \times 2$

$a(3) = 6 + 6$

$a(3) = 12$

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$a(4) = 6 + 3(4 - 1)$

$a(4) = 6 + 3 \times 3$

$a(4) = 6 + 9$

$a(4) = 15$