Since players are losing points every time they land on a red space, it is -50,
Here's our equation where c equals the amount of times.
-50C=-450
We need C by itself, we need to divide.
-450÷-50=9
Since there is no other way to lose points, we don't have to worry about the slope in this equation. But, there might be a way to gain points. We have it set at 0 assuming that Jamie did not score any points. This allows us to get the minimum times her could have landed.
The minimum number of times he could have landed on a red space is 9 times.
Answer:
4 is the maximum number of ride tickets she can buy
Step-by-step explanation:
Here, r represents the number of ride tickets and f represents number of food tickets.
The system of inequalities is given as:
r+f\geq 16 ....[1]
4r+2f\leq 40 .....[2]
To solve Mathematically:
Multiply equation [1] by -2 we have;
-2r-2f \leq -32 .....[3]
Add equation [2] and [3] we have;
2r \leq 8
Divide both sides by 2 we have;
r \leq 4
Since r must be less than or equal to 4.
You can also see the graph of the given system of inequalities as shown below.
The intersection point is, (4, 12)
Therefore, the maximum number of ride tickets she can buy is, 4
3 consecutive odd integers....x, x + 2, and x + 4
x + x + 4 = 3(x + 2) - 131
2x + 4 = 3x + 6 - 131
2x + 4 = 3x - 125
2x - 3x = - 125 - 4
-x = - 129
x = 129
x + 2 = 129 + 2 = 131
x + 4 = 129 + 4 = 133
so ur 3 odd numbers are : 129,131, and 133 <==
Answer:
n=8
Step-by-step explanation:
Answer:
You would use a^2 + b^2 = c^2
Step-by-step explanation:
a and b are the shorter side of the triangle whereas c is the hypotenuse or longest side of the triangle
