We notice a factor of 2x in both
2x(5x^2+4x-3)
trial and error
(5x-3)(x+1) yeilds 5x^2+2x-3, nope
(5x+3)(x-1) yeilds 5x^2-2x-3, nope
(5x-1)(x+3) yeilds 5x^2+14x-3, nope
(5x+1)(x-3) yeilds 5x^2-14x-3, nope
simplest form is
2x(5x^2+4x-3)
Answer: -3
mark me brainiest very easy answer
The probability that either the girls' or boys' team gets a game is 0.85
Step-by-step explanation:
Step 1:
Let P(G) represent the probability of girls team getting a game and P(B) represent the probability of the boys team getting a game.
P(B ∪ G) represents the probability of either girls and boys team getting a game.
P(B ∩ G) represents the probability of both girls and boys team getting a game.
Step 2:
It is given that P(G) = 0.8, P(B) = 0.7 and P(B ∩ G) = 0.65
We need to find the probability of either girls or boys team getting a game which is represented by P(B ∪ G)
Step 3:
P(B ∪ G) = P(B) + P(G) - P(B ∩ G)
= 0.8 + 0.7 - 0.65 = 0.85
Step 4:
Answer:
The probability that either the girls' or boys' team gets a game is 0.85
7.7 cm Because the sides of similar figures are in direct proportion to each other
Answer:
Divide X^2-14x+45 by x-9
Step-by-step explanation:
im just trying to get free points
