Answer:
a. attached graph; zero real: 2
b. p(x) = (x - 2)(x + 3 + 3i)(x + 3 - 3i)
c. the solutions are 2, -3-3i and -3+3i
Step-by-step explanation:
p(x) = x³ + 4x² + 6x - 36
a. Through the graph, we can see that 2 is a real zero of the polynomial p. We can also use the Rational Roots Test.
p(2) = 2³ + 4.2² + 6.2 - 36 = 8 + 16 + 12 - 36 = 0
b. Now, we can use Briott-Ruffini to find the other roots and write p as a product of linear factors.
2 | 1 4 6 -36
1 6 18 0
x² + 6x + 18 = 0
Δ = 6² - 4.1.18 = 36 - 72 = -36 = 36i²
√Δ = 6i
x = -6±6i/2 = 2(-3±3i)/2
x' = -3-3i
x" = -3+3i
p(x) = (x - 2)(x + 3 + 3i)(x + 3 - 3i)
c. the solutions are 2, -3-3i and -3+3i
Answer: ratio of her SAVINGS to her EXPENDITURE=1:7
Step-by-step explanation:
Neelam's daily income = ₹ 800
Neelam's daily savings amount = ₹100
Therefore her expenditure will be Daily income - Daily savings
= ₹ 800- ₹ 100= ₹ 700
ratio of her SAVINGS to her EXPENDITURE
= 100: 700
=1:7
Answer: No, it can never be greater. At most it can be equal though.
You have a bag containing 8 + 20 = 28 marbles.
After you pull a black marble you have 28 - 1 = 27 remaining marbles.
There are 20 yellow marbles in the bag.
The probability of pulling a yellow marble is now
Answer:
-20=k
Step-by-step explanation:
-14=k+6
-6 -6
-20=k
-14=-20+6
-14=-14