All categories

3 years ago

The GCF of 12 and 15 is _____.

Mathematics

2 answers:

Nikolay [14]3 years ago

6 0

Answer:

Step-by-step explanation:

sladkih [1.3K]3 years ago

4 0

Answer:

Step-by-step explanation:

To find the GCF of two numbers:

List the prime factors of each number.

Multiply those factors both numbers have in common. If there are no common prime factors, the GCF is 1.

Hope This Helps!

If you have anymore questions, Just ask me!

Mark Brainliest If anyone Else Answers Please to help me get to the next Rank!

#RoadToVituoso!

- Innverted

You might be interested in

Question 6 (1 point)

Shalnov [3]

2. Dividing exponential expression with the same base is what the left hand fractional expression is. Z^8/Z^?=z^6. Since all the bases are the same. To get the exponential power 6 on the right we subtract the denominator’s (bottom part of the fraction) exponential power (on the left) from the numerator’s (top part) exponential power.

Then, 8 - ? = 6? 2 is the only number to make the left equal the right side. This, z^8/z^2=z^6

8 0

3 years ago

Which of the following systems of linear equations has no solution?

yanalaym [24]

None of the above!!!!!!

8 0

3 years ago

Read 2 more answers

How do you simplify that question? For algebra 1.

motikmotik

$\left( \sqrt{x^{-3}} \right)^5 = \left( \sqrt{ \frac{1}{x^3} } \right)^5= \frac{1}{ (\sqrt{x^3})^5 } = \frac{1}{ \sqrt{x^{15}} } = \frac{1}{x^7 \sqrt{x} }$

<span>Explanation for the last step:</span>
$\sqrt{x^{15}}= \sqrt{x^{14}*x}= \sqrt{x^{14}}* \sqrt{x} =x^{ \frac{14}{2} }* \sqrt{x} =x^7 \sqrt{x}$

7 0

3 years ago

The radius of a circle is changing at the rate of 1/π inches per second. At what rate, in square inches per second, is the circl

MAXImum [283]

Answer:

10 square inches per second.

Step-by-step explanation:

The radius of the circle is given by the equation:

r(t) = (1/π in/s)*t

Where time in seconds.

Remember that the area of a circle of radius R is written as:

A = π*R^2

Then the area of our circle will be:

A(t) = π*( (1/π in/s)*t)^2 = π*(1/π in/s)^2*(t)^2

Now we want to find the rate of change (the first derivation of the area) when the radius is equal to 5 inches.

Then the first thing we need to do is find the value of t such that the radius is equal to 5 inches.

r(t) = 5 in = (1/ in/s)*t

5in*(π s/in) = t

5*π s = t

So the radius will be equal to 5 inches after 5*π seconds, let's remember that.

Now let's find the first derivate of A(t)

dA(t)/dt = A'(t) = 2*(π*(1/π in/s)^2*t = (2*π*t)*(1/π in/s)^2

Now we need to evaluate this in the time such that the radius is equal to 5 inches, we will get:

A'(5*π s) = (2*π*5*π s)*((1/π in/s)^2

= (10*π^2 s)*(1/π^2 in^2/s^2) = 10 in^2/s

The rate of change is 10 square inches per second.

4 0

3 years ago

The function f(x)=50⋅0.8x models the number of ants in Jonathan's ant farm after it is stricken by a deadly ant disease, where x

alina1380 [7]

Answer:

Step-by-step explanation:

In the exponential growth/decay function

$y=a(b)^x$ , in our situation,

y is the number of ants remaining in the colony after the growth or decay,

a is the initial number of ants in the colony, and

b is the growth/decay rate. Rule: if b is greater than 1, the function is growth; if b is greater than 0 but less than 1, the function is decay.

Our equation looks like this (it's given):

$y=50(.8)^x$

a = 50, which is the initial number of ants in the colony.

b = .8 (which actually means that then number of ants is declining by 20% each week). Since .8 is a fraction of 1, this is decay.

So far, we know that 1 and 4 are true. Let's look at 5. We have to do some solving to find out if it's true or not. If the number of ants after x = 2 weeks is 32, then we plug in 2 for x and see if the y we get as the answer is 32:

$y=50(.8)^2$ and

y = 50(.64) so

y = 32

5 is true as well. Let's test 6 by replacing x with 8 and seeing if y = 10:

$y=50(.8)^8$ and

y = 50(.16777216) so

y = 8.388

6 is not true.

1, 4, 5 are true

8 0

3 years ago

Read 2 more answers