Answer:
C. 55°
Step-by-step explanation:
Note the total measurement of angles for a triangle. The total measurement of all angles in a triangle = 180°
Note that m∠C is a right angle (as shown through the square), and that right angles = 90°
Subtract to find the measurement of the unknown angle (∠B)
∠B = 180 - (∠A + ∠C)
∠B = 180 - (35 + 90)
Simplify. Combine like terms. First, add (solve parenthesis), then subtract.
∠B = 180 - (125)
∠B = 55
m∠B = C. 55°
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Answer:
2.5 feet for each bow
Step-by-step explanation:
15/6= 2.5
For this case we must simplify the following expression:
We have that by definition of properties of powers that is fulfilled:
Then, rewriting the expression:
Answer:
Answer:
Step-by-step explanation:
8) (5x + 23) + (17x - 41) = 180
22x = 198
x = 9
arc JK 5(9) + 23 = 68°
arc MJ 17(9) - 41 = 112°
arc LMK 360 - 112 = 248
9) 8x + (21x - 12) + (10x + 9) + 90 = 360
39x = 273
x = 7
arc WX 21(7) - 12 = 135°
arc YW 90 + 8(7) = 146°
arc YX 10(7) + 9 = 79°
arc VXW 360 - 8(7) = 304°
<span>Assuming that the particle is the 3rd
particle, we know that it’s location must be beyond q2; it cannot be between q1
and q2 since both fields point the similar way in the between region (due to
attraction). Choosing an arbitrary value of 1 for L, we get </span>
<span>
k q1 / d^2 = - k q2 / (d-1)^2 </span>
Rearranging to calculate for d:
<span> (d-1)^2/d^2 = -q2/q1 = 0.4 </span><span>
<span> d^2-2d+1 = 0.4d^2 </span>
0.6d^2-2d+1 = 0
d = 2.72075922005613
d = 0.612574113277207 </span>
<span>
We pick the value that is > q2 hence,</span>
d = 2.72075922005613*L
<span>d = 2.72*L</span>
