Answer:
yes
Step-by-step explanation:
y = 79x - -37
37 = 79(0) - - 37
37 = 0 - - 37
37 = 37
To solve this function, all we need to do is substitute -4.3 in for wherever "x" appears and then simplify.
f(x) = 7.45x + 33.7; x = -4.3
f(-4.3) = 7.45(-4.3) + 33.7
f(-4.3) = -32.035 + 33.7
f(-4.3) = 1.665
This means that, when x = -4.3, f(x) = 1.665.
Note: It may help to remember that, in a function such as this, f(x) can be thought of as the "y" value that corresponds to the given "x" value (in fact, when writing it out with words, f(x) is the same as "function of x"). And, if you are given a value for f(x), then the opposite is true. Just substitute in the value given for f(x) and solve for x.
Hope this helps!
3+1=h i beev this because you are adding the amount of adults to children then that would get you to h
Answer:
A. 0
E. -3
F. 9
Step-by-step explanation:
You can't divide by 0; it is undefined. So if x cannot equal zero, then anything that turns the denominator to zero is an asymptote. Therefore, the roots of the cubic expression would be excluded, and we get our final answers.
Answer:
1) It is geometric
a) In each trial you can obtain 11 or obtain something else (and fail)
b) Throw 2 dices and watch if the result is 11 or not
c) The probability of success is 1/18
2) It is not geometric, but binomal.
Step-by-step explanation:
1) This is effectively geometric. When you see the sum of 2 dices, you can separate the result in two different outcomes: when the sum is 11 and when the sum is different from 11.
A trial is constituted bu throwing 2 dices and watching if the sum of the dices is 11 or not.
In order to get 11 you need one 5 in one dice and 1 six in another. As a consecuence, you have 2 favourable outcomes (a 5 in the first dice and a 6 in the second one or the other way around). The total amount of outcomes is 6² = 36, and all of them have equal probability. This means that the probability of success is 2/36 = 1/18.
2) This is not geometric distribution. The geometric distribution meassures how many tries do you need for one success. The amount of success in 10 trias follows a binomial distribution.
