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IrinaK [193]
3 years ago
11

write the linear equation point slope form for the line that is perpendicular to y = -2x+1 and has (4,2) as a solutien.

Mathematics
1 answer:
ladessa [460]3 years ago
7 0
Subtract 4 from both sides of the equation.

y=-4-2x+2

add -4 and +2.

the answer is

y=-2x-2

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The length of a rectangle is 2 cm longer than its width. if the perimeter of the rectangle is 40 cm , find its area.
rusak2 [61]

width = w

 length = w +2

perimeter = 2L + 2w

40 = 2(w+2) + 2w

40 = 2w+4 +2w

40 = 4w+4

36=4w

w=36/4 = 9

with = 9

length = 9+2 = 11


 area = l x w = 9*11 = 99 square cm

4 0
3 years ago
Rosario is rolling a six-sided number cube. Rosario rolls the number cube twice. What is the probability that Rosario gets the n
Marat540 [252]
It's a conditional probability

P( getting a given number AND getting again the same number)


P(of getting any number) =1/6
P(of getting once again the same number) 1/6 x 1/6 = 1/36
7 0
3 years ago
Read 2 more answers
How do u simplify this: sqrt =square root<br> 2sqrt462cd^2 * sqrt7c^5d^2
Sveta_85 [38]

Answer: The simplified version of this is 14d²c³√66

Step-by-step explanation:

6 0
2 years ago
Numero mixto de 16 -- 5
stealth61 [152]

Answer:

La respuesta correcta es 3 1/5

Step-by-step explanation:

Espero que esto ayude a marcar el MÁS CEREBRAL !!!

3 0
3 years ago
What is the fourth term in the binomial expansion (a+b)^6)
Dafna11 [192]

Answer:

20a^3b^3

Step-by-step explanation:

<u>Binomial Series</u>

(a+b)^n=a^n+\dfrac{n!}{1!(n-1)!}a^{n-1}b+\dfrac{n!}{2!(n-2)!}a^{n-2}b^2+...+\dfrac{n!}{r!(n-r)!}a^{n-r}b^r+...+b^n

<u>Factorial</u> is denoted by an exclamation mark "!" placed after the number. It means to multiply all whole numbers from the given number down to 1.

Example:  4! = 4 × 3 × 2 × 1

Therefore, the fourth term in the binomial expansion (a + b)⁶ is:

\implies \dfrac{n!}{3!(n-3)!}a^{n-3}b^3

\implies \dfrac{6!}{3!(6-3)!}a^{6-3}b^3

\implies \dfrac{6!}{3!3!}a^{3}b^3

\implies \left(\dfrac{6 \times 5 \times 4 \times \diagup\!\!\!\!3 \times \diagup\!\!\!\!2 \times \diagup\!\!\!\!1}{3 \times 2 \times 1 \times \diagup\!\!\!\!3 \times \diagup\!\!\!\!2 \times \diagup\!\!\!\!1}\right)a^{3}b^3

\implies \left(\dfrac{120}{6}\right)a^{3}b^3

\implies 20a^3b^3

7 0
2 years ago
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