Option A gives the correct answer.Step by step solution is listed below:
There you go, you didn’t show the representation but I drew one.
Answer:
Answer choice B
Step-by-step explanation:
The first three numbers, 1, 2, and 3, have an average of 5 dots, while the last two have an average of 1.5 dots. This means that there is a cluster at 1, 2, and 3, and it is apparent because there are simply so many more dots there than at 4 and 5.
Answer:
The proof is given below.
Step-by-step explanation:
Given a parallelogram ABCD. Diagonals AC and BD intersect at E. We have to prove that AE is congruent to CE and BE is congruent to DE i.e diagonals of parallelogram bisect each other.
In ΔACD and ΔBEC
AD=BC (∵Opposite sides of parallelogram are equal)
∠DAC=∠BCE (∵Alternate angles)
∠ADC=∠CBE (∵Alternate angles)
By ASA rule, ΔACD≅ΔBEC
By CPCT(Corresponding Parts of Congruent triangles)
AE=EC and DE=EB
Hence, AE is conruent to CE and BE is congruent to DE
Multiply one of them by -1 so one of the -2y is positive
-1(-7x-2y=-13)=7x+2y=13
Then add the two equations
7x+2y=13
+ x-2y=11
========
8x=24 - the 2y and -2y cancel out. Now solve for x
x=3 Now plug the x back into one of the equations
3-2y=11 Now solve for y
-2y=11-3
-2y=8
y=-4
So x=3 and y=-4
Hope this helps!