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Thepotemich [5.8K]
3 years ago
9

What is the equation of the line that passes through the point (-5,3)(−5,3) and has a slope of fraction -6/5

Mathematics
1 answer:
Allushta [10]3 years ago
5 0

Answer:

Step-by-step explanation:

Use the point-slope formula.

y - y_1 = m(x - x_1)  when :     x_1 = -5  and    y_1 =3 and   m= -6/5

the equation :   y - 3 = -6/5(x +5)

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Order the set of number from least to greatest .
earnstyle [38]

Answer (Please vote me Brainliest if this helps!):

The answer is D

Step-by-step explanation:

Lets start off with the square roots:

\sqrt{16} = 4

\sqrt{18} = 3\sqrt{2} = 4.24264...

Mixed fraction:

4\frac{2}{3} = 4.667

Therefore the answer is D.

6 0
3 years ago
Read 2 more answers
Sin(a)+sin(b)=sqrt(5/3) and cos(a)+cos(b)=1. Compute cos(a-b).
Reil [10]
Square both given expressions and add them together. Make use of trig identities.

  (sin(a) +sin(b))^2 = sin(a)^2 +2sin(a)sin(b) +sin(b)^2 = 5/3

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Adding, we have
  sin(a)^2 +cos(a^2) +2(cos(a)cos(b) +sin(a)sin(b)) +sin(b)^2 +cos(b)^2 = 2 2/3

Of course, the first and last pairs of terms are 1 and 1, and the middle product is 2cos(a-b), so you have
  1 + 2cos(a-b) +1 = 2 2/3
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6 0
3 years ago
My new speaker costs $154.00, but I also had to
const2013 [10]

Answer:

$247.94

Step-by-step explanation:

6 0
3 years ago
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If f and g are differentiable functions for all real values of x such that f(1) = 4, g(1) = 3, f '(3) = −5, f '(1) = −4, g '(1)
worty [1.4K]
Hello,

h(x)'=(f(x)*g(x))'=f'(x)*g(x)+f(x)*g'(x)
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Answer B

7 0
4 years ago
Can I get some help plz
julsineya [31]
3/50
2/40=1/20
compare
5 0
4 years ago
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