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3 years ago

A yard has a perimeter of 168 feet. If times the length of the yard equals seventeen times the width, what are its dimensions?

Mathematics

1 answer:

netineya [11]3 years ago

8 0

Answer: See Explanation

Step-by-step explanation:

Your question isn't complete but let's reframe it as:

A yard has a perimeter of 168 feet. If four times the length of the yard equals seventeen times the width, what are its dimensions?

Therefore, 2L + 2W = 168 ....... i

4L = 17W ........ ii.

From equation ii,

L = 17W/4 ........ iii

We would then slot the value of L into equation i

2L + 2W = 168

2(17W/4) + 2W = 168

17W/2 + 2W = 168

17W + 4W = 336

21W = 336

W = 336/21

W = 16

Since L = 17W/4

L = (17 × 16)/4

L = 68

The dimensions are 16 feet and 68 feet

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A yard has a perimeter of 168 feet. If times the length of the yard equals seventeen times the​ width, what are its​ dimensions?

A yard has a perimeter of 168 feet. If times the length of the yard equals seventeen times the width, what are its dimensions?