The answer is (3, -7). If the function is written in the form y = a(x –
h)^2 + k, the vertex will be (h, k). Let's write the function 8x^2 – 48x
+ 65 in the form of a(x – h)^2 + k. g(x) = 8x^2 – 48x + 65. g(x) = 8x^2
– 48x + 72 - 72 + 65. g(x) = (8x^2 – 48x + 72) - 7. g(x) = (8 * x^2 – 8
* 6x + 8 * 9) - 7. g(x) = 8(x^2 - 6x + 9) - 7. g(x) = 8(x - 3)^2 - 7.
The function is now in the form a(x – h)^2 + k, where a = 8, h = 3, and k
= -7. Thus, the vertex is (3, -7).
Given function is
now we need to find the value of k such that function f(x) continuous everywhere.
We know that any function f(x) is continuous at point x=a if left hand limit and right hand limits at the point x=a are equal.
So we just need to find both left and right hand limits then set equal to each other to find the value of k
To find the left hand limit (LHD) we plug x=-4 into 3x+k
so LHD= 3(-4)+k
To find the Right hand limit (RHD) we plug x=-4 into
so RHD= 
Now set both equal
k=-0.47
<u>Hence final answer is -0.47.</u>
Answer:
Standard Deviation = 5.928
Step-by-step explanation:
a) Data:
Days Hours spent (Mean - Hour)²
1 5 61.356
2 7 34.024
3 11 3.360
4 14 1.362
5 18 26.698
6 22 84.034
6 days 77 hours, 210.834
mean
77/6 = 12.833 and 210.83/6 = 35.139
Therefore, the square root of 35.139 = 5.928
b) The standard deviation of 5.928 shows how the hours students spend outside of class on class work varies from the mean of the total hours they spend outside of class on class work.
Answer:
z=3
Step-by-step explanation:
→32+76+24z=180[Sum of all sides of a triangle]
→108+24z=180
→24z=180-108
→z=72/24
→z=3
Answer:
The absolute deviation at 19 is 3.
Step-by-step explanation:
The absolute and mean absolute deviation show the amount of deviation (variation) that occurs around the mean score.
Since we are only interested in the deviations of the scores and not whether they are above or below the mean score, we can ignore the minus sign and take only the absolute value, giving us the absolute deviation.
We are asked to find the absolute deviation at 19.
the given mean is 16.
Hence, the deviation is:
19-16= -3.
Hence the absolute deviation at 19 is |-3|=3.
