Answer:
Step-by-step explanation:
√108 ÷ √125 + √75
= 6√3 ÷ 5√5 + 5√3
= 11√3 / 5√5
hope this helps
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Answer:
Step-by-step explanation:
The answer is actually
Let:
S=1+2+3+4+5+6+7+8+9+n
We know the answer to the following infinite sum:
S2=1-1+1-1+1-1+1-1+1-1+1-1+1-....= - 1/2
We can therefore solve for this sum:
S3=1-2+3-4+5-6+7-8+9-....
We add them:
S3= 1-2+3-4+5-6+7-8...
S3= +1-2+3-4+5-6+7-8...
________________
2S3= 1-1+1-1+1-1+1-1+1-....
Therefore:
2S3=S2=
10 is the answer because using the Pythagorean theorem 6^2 + 8^2 = 100. The square root of 100 would be 10
Answer:
The probability that the person will not be a senior
P(E⁻) = 1 - P(E)
= 
Step-by-step explanation:
<u><em>Explanation</em></u>:-
Given A high school club has 10 members who are seniors and 8 members who are juniors
n(S) = 10 + 8 = 18
If a member is randomly selected to be the club president
Let 'E' be the event that the person will be a senior
The probability that the person will be a senior


The probability that the person will not be a senior
P(E⁻) = 1 - P(E)
= 