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Anuta_ua [19.1K]
3 years ago
11

Using the formula A=P(1+r/n) ^nt calculate the value of an initial investment of $4,500 after 10 years at 4% interest, compounde

d quarterly (four times per year).
Mathematics
1 answer:
Tema [17]3 years ago
6 0

Answer:

Using the formula provided, the value of that investment after 10 years is

A = P(1 + r/n) ^nt

   = 4500 x (1 + (4/100)/4)^(10 x 4)

   = 4500 x (1.01)^40

   = 6699.89$

Hope this helps!

:)

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Something on sale for $725. The original price was $1299. To the nearest tenth of a percent, what was the rate of discount?
ElenaW [278]

Answer:

44.2%

Step-by-step explanation:

Rate of discount = (difference in prices / original price) x 100

Difference in price = $1299 - $725 = $574

Original price = $1299

($574 / $1299) x 100 = 44.187837%

the tenth is the first number after the decimal place. To convert to the nearest tenth, look at the number after the tenth (the hundredth). If the number is greater or equal to 5, add 1 to the tenth figure. If this is not the case, add zero

the hundredth figure is 8, which is greater than 5. 1 would be added to the tenth figure.

So it becomes 44.2%

4 0
2 years ago
PLEASE HELP SO I CAN PASS MY TEST
Brums [2.3K]

Answer:

10

Step-by-step explanation:

The first thing to do would be to find how many 1/4 cups are in the 1 cup. Divide 1 by 1/4 and you'd get 4.

Just multiply 2 1/2 by 4 and you get 10

8 0
3 years ago
Read 2 more answers
Write two expressions that are equivalent to 2(x+4)​
kotegsom [21]

(x+4)+(x+4)

2(x+2(2)) the (2) would be the exponent for 2 in the second one.

8 0
3 years ago
The height h (in feet) of an object dropped from a ledge after x seconds can be modeled by h(x)=−16x2+36 . The object is dropped
kakasveta [241]

Check the picture below.

\bf ~~~~~~\textit{initial velocity in feet} \\\\ h(t) = -16t^2+v_ot+h_o \quad \begin{cases} v_o=\textit{initial velocity}&\\ \qquad \textit{of the object}\\ h_o=\textit{initial height}&\\ \qquad \textit{of the object}\\ h=\textit{object's height}&\\ \qquad \textit{at "t" seconds} \end{cases}

so the object hits the ground when h(x) = 0, hmmm how long did it take to hit the ground the first time anyway?

\bf h(x)=-16x^2+36\implies \stackrel{h(x)}{0}=-16x^2+36\implies 16x^2=36 \\\\\\ x^2=\cfrac{36}{16}\implies x^2 = \cfrac{9}{4}\implies x=\sqrt{\cfrac{9}{4}}\implies x=\cfrac{\sqrt{9}}{\sqrt{4}}\implies x = \cfrac{3}{2}~~\textit{seconds}

now, we know the 2nd time around it hit the ground, h(x) = 0, but it took less time, it took 0.5 or 1/2 second less, well, the first time it took 3/2, if we subtract 1/2 from it, we get 3/2 - 1/2  = 2/2 = 1, so it took only 1 second this time then, meaning x = 1.

\bf ~~~~~~\textit{initial velocity in feet} \\\\ h(x) = -16x^2+v_ox+h_o \quad \begin{cases} v_o=\textit{initial velocity}&0\\ \qquad \textit{of the object}\\ h_o=\textit{initial height}&\\ \qquad \textit{of the object}\\ h=\textit{object's height}&0\\ \qquad \textit{at "t" seconds}\\ x=\textit{seconds}&1 \end{cases} \\\\\\ 0=-16(1)^2+0x+h_o\implies 0=-16+h_o\implies 16=h_o \\\\[-0.35em] ~\dotfill\\\\ ~\hfill h(x) = -16x^2+16~\hfill

quick info:

in case you're wondering what's that pesky -16x² doing there, is gravity's pull in ft/s².

4 0
3 years ago
Mrs. Cook is a teacher whose salary is $23,125 for a 185-day school year. In Mrs. Cook's school district, substitute teachers ar
yawa3891 [41]

Answer:

35

Step-by-step explanation:

23,125/185= 125

125-90 = 35

5 0
3 years ago
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