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lianna [129]
3 years ago
8

What is the absolute refractory period? Choose the correct option. a. The period when the firing frequency is at about 1000 Hz b

. The time period of about 1 msec after an action potential before another one can be initiated c. The time period of several milliseconds when it is difficult to initiate another action potential due to sodium channel inactivation d. The time period when the membrane potential stays hyperpolarized until the voltage-gated potassium channels close
Chemistry
1 answer:
Phoenix [80]3 years ago
7 0

Answer:  The time period of about 1 msec after an action potential before another one can be initiated -----b

Explanation:Absolute refractory period is the time after an action potential onset when no amount or how strong a stimulus is can cause  a second action potential. it is always the time period of 1 m sec between an initiated action potential and an impending  next initiated one with the the maximum firing frequency at about  1000 impulses per second.

The absolute refractory period is as a result  of molecular processes that triggers the action potential known as sodium channels(tiny pore nerves) . Now the sodium channels exist in three states which are open, close and inactivated states. At rest, the sodium channel is closed, but when a there is an electrical  stimulation, the sodium channel opens up to respond to that stimulus which after it passes to the inactivated state, in which the the spores are closed and  no matter how strong or the amount an impending next stimulus is, will not cause the pore to open until it has recovered and returned back to the closed state.

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How much heat is required to raise the temperature of 670g of water from 25.7"C to 66,0°C? The specific heat
inna [77]

Answer:

Explanation:

q= mc theta

where,

Q = heat gained

m = mass of the substance = 670g

c = heat capacity of water= 4.1 J/g°C    

theta =Change in temperature=( 66-25.7)

Now put all the given values in the above formula, we get the amount of heat needed.

q= mctheta

q=670*4.1*(66-25.7)

  =670*4.1*40.3

=110704.1

8 0
4 years ago
please help timed !! due rn !! What happens to particle motion as two substances come to thermal equilibrium?
Gennadij [26K]

Answer:

When two substances that are of different temperatures are brought together and there is heat transfer such that the substances come to thermal equilibrium, the effect on the particle motion are as follows

1) The particle motion of the hotter body reduces, because its temperature reduces

2) The particle motion of the colder body increases, because its temperature increases

3) For gases, the volume and or pressure reduces for the hotter body, and if the temperature of the gas falls below the boiling point temperature, the gas will change into liquid

For the colder gas, only the volume and or pressure increases and the temperature rises

4) For liquids, if the temperature of the hotter liquid falls below the melting point, the hotter liquid will become a frozen solid

For the the colder liquid, if the temperature is raised above the boiling point, the liquid changes into gas and the temperature does not rise above the boiling point temperature, until all the cold liquid has evaporated

5) For solids, the vibration of the particles of the hotter substance reduces and the solid becomes more brittle

For the colder body, the rise in temperature causes an increase in vibration of the particles, and if the temperature rises above the melting point, the colder solid will begin to melt

Explanation:

7 0
3 years ago
How many grams of Sodium metal are required to completely react with 100 g of Magnesium chloride hexahydrate in a single replace
slava [35]

Answer:

MgCl2 - 6H2O

203.3 mol

MgCl2 + 2Na = 2NaCl + Mg

22.6g

Explanation:

1. Write the formula of hydrate and find molar mass.

2. Write a balanced single replacement (don't include H2O)

3. Do the given/wanted calculation (include H2O in molar mass of given)

6 0
3 years ago
Propanoic acid, ch3ch2cooh, has a pka =4.9. draw the structure of the conjugate base of propanoic acid and give the ph above whi
xenn [34]

Conjugate base of Propanoic acid (CH_{3}CH_{2}COOH is propanoate where -COOH group gets converted to -COO^{1-}. The structure of conjugate base of Propanoic acid is shown in the diagram.

The p^{H} above which 90% of the compound will be in this conjugate base form can be determined using Henderson's equation as propanoic acid is weak acid and it can form buffer solution on reaction with strong base.

p^{H}= p^{k_{a}+ log\frac{[Conjugate base]}{[acid]}=4.9+log\frac{90}{10}=5.85

As 90% conjugate base is present, so propanoic acid present 10%.

8 0
4 years ago
Which statement is true regarding the diagram of circle P? The sum of y and z must be 2x. The sum of y and z must be x. The diff
olga2289 [7]

Answer:

The difference of Z and Y must be 2x

Explanation:

6 0
3 years ago
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