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lidiya [134]
3 years ago
14

What is true about all chemical equations? Links are reported

Chemistry
1 answer:
Vanyuwa [196]3 years ago
6 0

Answer:Your answer is A

Explanation:

Hope this helps ツ

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Question 16 A chemistry graduate student is given of a methylamine solution. Methylamine is a weak base with . What mass of shou
julsineya [31]

Answer:

90 g CH₃NH₃Cl

Explanation:

It appears your question lacks the values required to solve this problem. However, an online search tells me these are the values. Be aware if your values are different your answer will also be different, but the methodology remains the same.

" A chemistry graduate student is given 450 mL of a 1.70 M methylamine solution. Methylamine is a weak base with Kb=4.4x10⁻⁴. What mass of CH₃NH₃Cl should the student dissolve in the methylamine solution to turn it into a buffer with pH = 10.40 ? You may assume that the volume of the solution doesn't change when the is dissolved in it. Be sure your answer has a unit symbol, and round it to 2 significant digits. "

We'll use the <u>Henderson-Hasselbach equation</u>:

  • pH = pKa + log\frac{[Methylamine]}{[Salt]}

So first we <u>use Kb to calculate Ka and then pKa</u>:

  • Ka = Kw/Kb ⇒ Ka = 1x10⁻¹⁴/4.4x10⁻⁴ = 2.27x10⁻¹¹
  • pKa = -log(Ka) = 10.64

Now we can <u>calculate the concentration of the salt</u>, CH₃NH₃Cl:

  • pH = pKa + log\frac{[Methylamine]}{[Salt]}
  • 10.40 = 10.64 + log\frac{1.70}{[Salt]}
  • -0.24 = log\frac{1.70}{[Salt]}
  • 10^{-0.24}=\frac{1.70}{[Salt]}
  • [Salt] = 2.95 M

Now we use the final volume to <u>calculate the moles of CH₃NH₃Cl and finally its mass</u>, using its molecular weight:

  • 450 mL ⇒ 450/1000 = 0.450 L
  • 2.95 M * 0.450 L = 1.3275 mol CH₃NH₃Cl
  • 1.3275 mol CH₃NH₃Cl * 67.45 g/mol = 89.54 g CH₃NH₃Cl

Which when rounded to 2 significant digits becomes 90 g CH₃NH₃Cl

7 0
3 years ago
If I use the answers from here wouldn't that come up as a high % plagiarism ??
damaskus [11]

Answer:

No

Explanation:

My sister uses this all the time and it is perfectly safe

6 0
2 years ago
Read 2 more answers
Theobromine, C7H8N4O2, is a component of chocolate. It is mildly diuretic, is a mild stimulant, and relaxes the smooth muscles o
Ierofanga [76]

Answer:

3.6\times 10^{-4} moles of Threobromine are present in chocolate bar

Explanation:

Molar mass of Theobromine = (7\timesmolar mass of C)+(8\timesmolar mass of H)+(4\timesmolar mass of N)+(2\timesmolar mass of O) = (7\times12g/mol)+(8\times1g/mol)+(4\times14g/mol)+(2\times16g/mol) = 180 g/mol

We know that, number of moles of a compound is the ratio of mass to molar mass of the compound.

So, 0.064 g of Threobromine = \frac{0.064}{180} moles of Threobromine = 3.6\times 10^{-4} moles of Threobromine

8 0
3 years ago
Atp can be used as the cell's energy exchange mechanism because
SCORPION-xisa [38]
Because energy is needed to alive so when glucose goes into oxygen cells it provides energy in the form of Atp
6 0
3 years ago
What elements are denser than air
trapecia [35]
Lots of things are such as mercury water etc.
4 0
3 years ago
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