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Gwar [14]
3 years ago
13

Which balanced equation represents a chemical change?

Chemistry
1 answer:
GarryVolchara [31]3 years ago
4 0

Okay, so what you first do with this  type of question is think about what a chemical change is. A chemical change is a change that can not be reversed. A physical change is something that can be reversed or done using temperature. e.x. Water freezing into ice is a physical change, where as combining vinegar and baking soda together releases a gas, which is chemical, or iron rusting in the presence of oxygen.  Which one of these equations has one chemical molecule set that produces a different set?


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I don’t understand your questions can you elaborate
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John Dalton thought that atoms
zloy xaker [14]

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cannot be broken down further

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2 years ago
Will magnesium and fluorine atoms most likely form an ionic bond or a covalent bond?
Andreas93 [3]

Answer:

Ionic bond

Explanation:

The magnesium atom gives up 2 electrons to form a magnesium ion, Mg2+ . The two electrons are transferred to fluorine atoms to form two fluoride ions, F–.

6 0
4 years ago
Read 2 more answers
How many grams of lithium chloride can be produced from 14.3 g of lithium chlorate when it decomposes into lithium chloride and
vampirchik [111]

6.7 grams of lithium chloride will be produced.

<h3><u>Explanation:</u></h3>

Lithium chlorate is LiClO₃ and lithium chloride is LiCl. The reaction is,

2LiClO₃ = 2LiCl +3O₂.

So here, 2 moles of lithium chlorate produces 2 moles of lithium chloride.

Or, one molecule of lithium chlorate will produce one mole of lithium chloride.

Molecular weight of lithium chlorate =6.9 + 35.5 + 16\times3 = 90.4.

So, 14.3 grams of lithium chlorate has 0.16 moles of lithium chlorate.

Thereby, moles of lithium chloride produced is 0.16 moles.

Molecular weight of lithium chloride = 6.9+35.5 = 42.4 grams.

So weight of lithium chloride produced = 42.4 \times 0.16 = 6.7 grams.

Thus, weight of lithium chloride produced will be 6.7 grams.

3 0
4 years ago
Consider a galvanic cell consisting of the following two redox couplesAlB+ 3e Al , Mga + 2e Mg, (ag. E® = 1.676 V ) E° = 2.356 V
malfutka [58]

Answer:

0.68 V

Explanation:

For anode;

3Mg(s) ---->3Mg^2+(aq) + 6e

For cathode;

2Al^3+(aq) + 6e -----> 2Al(s)

Overall balanced reaction equation;

3Mg(s) + 2Al^3+(aq) ----> 3Mg^2+(aq) + 2Al(s)

Since

E°anode = -2.356 V

E°cathode = -1.676 V

E°cell=-1.676 -(-2.356)

E°cell= 0.68 V

4 0
3 years ago
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