Answer:
Option B. minimum is correct for the first blank
Option C. 6 is correct for second blank.
Step-by-step explanation:
In order to find the maxima or minima of a function, we have to take the first derivative and then put it equal to zero to find the critical values.
Given function is:
Taking first derivative
Now the first derivative has to be put equal to zero to find the critical value
The function has only one critical value which is 5.
Taking 2nd derivative
As the value of 2nd derivative is positive for the critical value 5, this means that the function has a minimum value at x = 5
The value can be found out by putting x=5 in the function
Hence,
<u>The function y = x 2 - 10x + 31 has a minimum value of 6</u>
Hence,
Option B. minimum is correct for the first blank
Option C. 6 is correct for second blank.
Answer:
80
Step-by-step explanation:
first, put in (5x-4) for the x in g(x).
g(f(x))=(5x-4)^2 -1
now, FOIL and simplify.
25x^2-40x+16-1
25x^2-40x+15
now, plug in -1 for x.
25(-1)^2-40(-1)+15
25+40+15
80
A) 25/24 because i don’t know i’m just doing this to get points
Answer:
a°=79°[alternate angles]
c°=83°[alternate angle]
a° +d°=180°[straight angle]
79°+d°=180
or,d°=180-79
so,d°=101°
Now,
b°+c°=170°[sum of straight angle]
b°+83°=180°
b°=180°-83°
so,b°=97°
Answer:3
x
−
2
y
=
7
Explanation:
Write the standard form of the line that goes through
(
3
,
1
)
and is perpendicular to
y
=
−
2
3
x
+
4
.
The equation
y
=
−
2
3
x
+
4
is in slope intercept form
y
=
m
x
+
b
where
m
= slope and
b
= the
y
intercept.
The slope of this line is then
m
=
−
2
3
A perpendicular slope is the opposite sign reciprocal. So, we change the sign of
−
2
3
and switch the numerator and denominator.
Perpendicular slope
m
=
3
2
To find the equation of the new line, use the point slope equation
y
−
y
1
=
m
(
x
−
x
1
)
where
m
=
slope and
(
x
1
,
y
1
)
is a point.
The slope is
3
2
and the point is the given point
(
3
,
1
)
.
y
−
1
=
3
2
(
x
−
3
)
a
a
a
Distribute
y
−
1
=
3
2
x
−
9
2
Standard form is
a
x
+
b
y
=
c
where
a
,
b
and
c
are integers and
a
is positive.
a
a
2
(
y
−
1
=
3
2
x
−
9
2
)
a
a
a
Multiply the equation by
2
a
a
a
a
a
2
y
−
2
=
3
x
−
9
−
3
x
a
a
a
a
a
a
a
−
3
x
a
a
a
Subtract
3
x
from both sides
−
3
x
+
2
y
−
2
=
−
9
a
a
a
a
a
a
a
a
+
2
a
a
a
+
2
a
a
a Add 2 to both sides −
3
x
+
2
y
=
−
7
−
1
(
−
3
x
+
2
y
=
−
7
)
a
a
a
Multiply the equation by −
1
3
x
−
2
y
=
7
