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3 years ago

Please help me I need help

Mathematics

1 answer:

snow_tiger [21]3 years ago

5 0

d = 16.76 inches

Step-by-step explanation:

We can extend the definition of the Pythagorean theorem to 3-dimensions:

$d = \sqrt{ {x}^{2} + {y}^{2} + {z}^{2} }$

Let x = 10 in

y = 10 in

z = 9 in

$d = \sqrt{ {(10)}^{2} + {(10)}^{2} + {(9)}^{2} }$

$d = \sqrt{281} = 16.76 \: in$

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Step-by-step explanation:

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3 years ago

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3 years ago

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3 years ago

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We have given that,Kaylib’s eye-level height is 48 ft above sea level, and addison’s eye-level height is 85 and one-third ft above sea level.

We have to find the how much farther can addison see to the horizon

<h3>Which equation we get from the given condition?</h3>

$d=\sqrt{\frac{3h}{2} }$

Where, we have

d- the distance they can see in thousands

h- their eye-level height in feet

For Kaylib

$d=\sqrt{\frac{3\times 48}{2} }\\\\d=\sqrt{{3(24)} }\\\\\\d=\sqrt{72}\\\\d=\sqrt{36\times 2}\\\\\\d=6\sqrt{2}....(1)$

For Addison h=85(1/3)

$d=\sqrt{\frac{3\times 85\frac{1}{3} }{2} }\\d\sqrt{\frac{256}{2} } \\d=\sqrt{128} \\d=8\sqrt{2} .....(2)$

Subtracting both distances we get

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Therefore, the addison see to the horizon at 2 root 2mi.

To learn more about the eye level visit:

brainly.com/question/1392973

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3 years ago