What is the answer please hurry I have only 3 minutes to answer correct with a simple answer

An assembly consists of two mechanical components. Suppose that the probabilities that the first and second components meet spec

harkovskaia [24]

Answer:

P(X = 0) = 0.0208, P(X = 1) = 0.2484, P(X = 2) = 0.7308

Step-by-step explanation:

Let's define the following events

A: the first component meet specification

B: the second component meet specification

P(A) = 0.87

P(B) = 0.84

Let X be the random variable that represents the number of components in the assembly that meet specifications. Because there are only two mechanical components in the assembly, X can only take the values 0, 1, 2.

P(X = 0) = P(the first component does not meet specification and the second component does not meet specification) =

$P(A^{c}\cap B^{c}) = P(A^{c})P(B^{c})$ (because of independence)

= (0.13)(0.16) = 0.0208

P(X = 1) = P(only one component meet specification) = P[(the first component meet specification and the second component does not meet specification) or (the first component does not meet specification and the second component meet specification)] =

$P[(A\cap B^{c})\cup (A^{c}\cap B)] = P(A\cap B^{c}) + P(A^{c}\cap B)=$ (because sets are mutually exclusive)

$P(A)P(B^{c}) + P(A^{c})P(B)=$ (because of independence)

= (0.87)(0.16) + (0.13)(0.84) = 0.2484

P(X = 2) = P(both components meet specifications) =

$P(A\cap B) = P(A)P(B)$ (because of independence)

= (0.87)(0.84)

= 0.7308

8 0

3 years ago

Find the answer and explain.560.450-34.34872

gladu [14]

Answer:526.101

Step-by-step explanation:

To find 560.450-34.34872

=526.101

That is u subtract 560.450-34.34872

We get

=526.101

5 0

3 years ago

Which equation can be used to determine p, the cost of t towels?

OverLord2011 [107]

I'm pretty sure the answer is B t=8.50+p

6 0

3 years ago

Simplify: -4x542x5

dimaraw [331]

multiply left to right:

-4 x 542 = -2,168

-2,168 x 5 = -10,840

answer: -10,840

6 0

2 years ago

Over the summer a bunch of math teachers from different schools got together for a BBQ. Not one of the teachers knew each other

lisov135 [29]

The first partner in the handshake can be any one of 15 people.
The second partner can be any one of 14 people.
So the total number of possible arrangements is (15 x 14) = 210 .

BUT . . . .

If Mr. Smith and Mr. Jones are shaking hands, it doesn't matter which one is the first partner and which one is the second partner ... It's the same handshake either way.

That number of ' 210 ' up above counted both ways separately. The real number of handshakes between different people is half of that 210/2 = 105 handshakes.

5 0

3 years ago