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UkoKoshka [18]
3 years ago
10

Given equations A and B as 2/3x + 3/5y = 12 and 5/2y - 3x = 6 , respectively, which expression will eliminate the variable y?. .

A. 5/3A + 2/5B . B. 5/3A - B. C. A - 2/5B. D. 5/3A - 2/5B . E. 25/15A + 6/15B
Mathematics
1 answer:
spayn [35]3 years ago
5 0
We are given with the expressions A as 2/3x + 3/5y = 12 and B as 5/2y - 3x = 6. To eliminate y, we should multiply each function with a number that when the two functions are added, y cancels out. In this case, we multiply A by 5/3 and B by -2/5. Hence the answer is D. <span>D. 5/3A - 2/5B</span>
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Step-by-step explanation:

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Determine the type and number of solutions of 4x^2-5x+1=0
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4x^2-5x=-1

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Answer the following questions regarding the graphed inequality.
arsen [322]

Answer:

m = 0.5, b = 2, greater than symbol >

Step-by-step explanation:

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The area above the line is shaded in. This is to show that all values greater than the line are applicable, so we will use the greater than symbol, >

3 0
3 years ago
Rowing upstream for 5 mi against a strong current, your speed is 20% less than your normal rowing speed. On the return trip down
spayn [35]

Answer:

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Step-by-step explanation:

3 0
3 years ago
PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!!
aev [14]

Answer: (B) -625

<u>Step-by-step explanation:</u>

Given the sequence {-500, -100, -20, -4, -0.8, ... }, we know that that the first term (a) is -500 and the ratio (r) is \dfrac{-100}{-500}=\dfrac{1}{5}

Input those values into the Sum formula:

S_n=\dfrac{a(1-r^n)}{1-r}\\\\S_8=\dfrac{-500\bigg(1-\dfrac{1}{5}^n\bigg)}{1-\dfrac{1}{5}}\\\\.\quad=\dfrac{-500\bigg(1-\dfrac{1}{390,625}\bigg)}{\dfrac{4}{5}}\\\\.\quad=\dfrac{-500\bigg(\dfrac{390,624}{390,625}\bigg)}{\dfrac{4}{5}}\\\\.\quad=\dfrac{5(-500)(390,624)}{4(390,625)}\\\\.\quad=-624.998\\\\.\quad=-625\quad \text{(rounded to 2 decimal places)}

4 0
4 years ago
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