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UkoKoshka [18]
3 years ago
10

Given equations A and B as 2/3x + 3/5y = 12 and 5/2y - 3x = 6 , respectively, which expression will eliminate the variable y?. .

A. 5/3A + 2/5B . B. 5/3A - B. C. A - 2/5B. D. 5/3A - 2/5B . E. 25/15A + 6/15B
Mathematics
1 answer:
spayn [35]3 years ago
5 0
We are given with the expressions A as 2/3x + 3/5y = 12 and B as 5/2y - 3x = 6. To eliminate y, we should multiply each function with a number that when the two functions are added, y cancels out. In this case, we multiply A by 5/3 and B by -2/5. Hence the answer is D. <span>D. 5/3A - 2/5B</span>
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6(5x - 3) + 2 = 14 what's the answer?
Lubov Fominskaja [6]

Answer:

x=1

Step-by-step explanation:

6(5x - 3) + 2 = 14

Subtract 2 from each side

6(5x - 3) + 2-2 = 14-2

6(5x - 3)  = 12  

Divide each side by 6

6(5x - 3) /6 = 12/6

5x-3 = 2

Add 3 to each side

5x-3+3 = 2+4

5x=5

Divide each side by 5

5x/5 = 5/5

x = 1

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3 years ago
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4vir4ik [10]

Answer:

Step-by-step explanation:

5 0
3 years ago
2a²+5b²<br> a=-6<br> b=2<br> Please help!!
stich3 [128]

2a^2+5b^2

2(-6)^2+5(2)^2

2(36)+5(4)

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6 0
3 years ago
The cylinders are similar. The volume of the larger cylinder is 2264 cubic centimeters. What is the volume of the smaller cylind
LenaWriter [7]

\bf ~\hspace{5em} \textit{ratio relations of two similar shapes} \\[2em] \begin{array}{ccccllll} &\stackrel{ratio~of~the}{Sides}&\stackrel{ratio~of~the}{Areas}&\stackrel{ratio~of~the}{Volumes}\\ \cline{2-4}&\\ \cfrac{\textit{similar shape}}{\textit{similar shape}}&\cfrac{s}{s}&\cfrac{s^2}{s^2}&\cfrac{s^3}{s^3} \end{array}\\\\[-0.35em] ~\dotfill


\bf \cfrac{\textit{similar shape}}{\textit{similar shape}}\qquad \cfrac{s}{s}=\cfrac{\sqrt{s^2}}{\sqrt{s^2}}=\cfrac{\sqrt[3]{s^3}}{\sqrt[3]{s^3}}\\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \cfrac{s}{s}=\cfrac{4}{8}\implies \cfrac{s}{s}=\cfrac{1}{2}~\hspace{7em}\cfrac{1}{2}=\cfrac{\sqrt[3]{x}}{\sqrt[3]{2264}}\implies \cfrac{1}{2}=\sqrt[3]{\cfrac{x}{2264}} \\\\\\ \left( \cfrac{1}{2} \right)^3=\cfrac{x}{2264}\implies \cfrac{1}{8}=\cfrac{x}{2264}\implies \cfrac{2264}{8}=x\implies 283=x

4 0
3 years ago
For her college fund jenny's parents invested $5000 four years ago. the account has now reached $6312. what is the approximate a
Tasya [4]

Answer:

Rate = 6.56%

Step-by-step explanation:

Principal (P) = $5000

Interest (I) = $6312

Time (T) = 4 years

Rate (r) = ?

This question is involves simple interest and with the formula, we can easily plug in the values to find the rate.

S.I = P(1 + rt)

S.I = simple interest

P = principal

R = Rate

T = Time

6312 = 5000(1 + r*4)

6312 = 5000 + 5000*4r

6312 - 5000 = 20000r

1312 = 20000r

r = 1312 / 20000

r = 0.0656

Rate are calculated in percentage hence we'll multiply it by 100

R = 6.56%

4 0
3 years ago
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