Answer:
629.92 ![cm^3](https://tex.z-dn.net/?f=cm%5E3)
Step-by-step explanation:
The minimum volume of the can that can hold 4 tennis balls must have at least the same volume as 4 tennis balls.
The volume of one tennis ball, V = ![\frac{4}{3}\pi r^3](https://tex.z-dn.net/?f=%5Cfrac%7B4%7D%7B3%7D%5Cpi%20%20r%5E3)
where r = radius of the tennis ball
The diameter of a ball = 6.7 cm
Its radius will be = 6.7 / 2 = 3.35 cm
Volume, V, will be:
![V = \frac{4}{3}\pi (3.35)^3](https://tex.z-dn.net/?f=V%20%3D%20%5Cfrac%7B4%7D%7B3%7D%5Cpi%20%20%283.35%29%5E3)
V = 157.48![cm^3](https://tex.z-dn.net/?f=cm%5E3)
Hence, the volume of 4 balls will be:
4 * V = 4 * 157.48 = 629.92 ![cm^3](https://tex.z-dn.net/?f=cm%5E3)
The minimum volume that the cylindrical can has to have is 629.92
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Answer:
Step-by-step explanation:I think the answer is D.
Answer:
Step-by-step explanation:
![(\pi)\left(\frac{60}{360} \right)(9^{2})=\boxed{13.5\pi}](https://tex.z-dn.net/?f=%28%5Cpi%29%5Cleft%28%5Cfrac%7B60%7D%7B360%7D%20%5Cright%29%289%5E%7B2%7D%29%3D%5Cboxed%7B13.5%5Cpi%7D)
Answer:
it's probably ours it's just a lucky guess
Step-by-step explanation: