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katen-ka-za [31]
3 years ago
5

In what time will 64000 amount to 68921 at a rate of 5 % per annum comp half yearly

Mathematics
2 answers:
andre [41]3 years ago
4 0

Answer:

Time = T half–years , Rate = 5 % per half year

2

love history [14]3 years ago
4 0

Step-by-step explanation:

we know the formula:

  1. A=P(1+r/n)^nt ,where A is the amount , P is the principle , r is the rate , n is the number of times the interest compounded per unit time

68921=64000(1+0.05/2)^2t

or,68921/64000=(41/40)^2t

or, (41/40)^3=(41/40)^2t

or 2t=3

or, t=3/2 years

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Can someone help with #3 and show your work !!
ioda
If s represents the number of songs Kim downloads, her expenses for a month must satisfy the inequality
  5.00 + 0.58·s ≤ 13.00

To solve this, subtract 5.00 to get the s-term by itself, then divide by the coefficient of s.
  0.58·s ≤ 8.00
  s ≤ 8.00/0.58 ≈ 13.79
The number of songs must be an integer, so we conclude Kim can download 13 songs, but not 14 songs.

Kim can download 13 songs without exceeding her budget.
8 0
3 years ago
Read 2 more answers
B. − 4 = 7 and − 4 + 4 = 7 + 4
daser333 [38]

Answeration:

they are both false

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3 years ago
Write the equation of the line that passes through the points (4,-6) and (-2,3)
yarga [219]

Here is your answer and an explanation

Answer: y = -2/3x

Explanation:

This can be determined by calculating the gradient of the straight line, using:

m=ΔyΔx

=−6−34−(−2)

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=−32

Then we use the slope-point form of the straight line:

y−y1=m(x−x1)

to give:

y−3=−32(x−(−2))

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7 0
2 years ago
Help please with algebra problem
Strike441 [17]
Number of weekend minutes used: x
Number of weekday minutes used: y

This month Nick was billed for 643 minutes:
(1) x+y=643

The charge for these minutes was $35.44
Telephone company charges $0.04 per minute for weekend calls (x)
and $0.08 per minute for calls made on weekdays (y)
(2) 0.04x+0.08y=35.44

We have a system of 2 equations and 2 unkowns:
(1) x+y=643
(2) 0.04x+0.08y=35.44

Using the method of substitution
Isolating x from the first equation:
(1) x+y-y=643-y
(3) x=643-y

Replacing x by 643-y in the second equation
(2) 0.04x+0.08y=35.44
0.04(643-y)+0.08y=35.44
25.72-0.04y+0.08y=35.44
0.04y+25.72=35.44

Solving for y:
0.04y+25.72-25.72=35.44-25.72
0.04y=9.72

Dividing both sides of the equation by 0.04:
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y=243

Replacing y by 243 in the equation (3)
(3) x=643-y
x=643-243
x=400


Answers:
The number of weekends minutes used was 400
The number of weekdays minutes used was 243
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