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lozanna [386]
4 years ago
14

A 15-foot ladder is leaning against a 30-foot wall. The bottom end of the ladder is 9 feet from the wall. How many feet above th

e ground does the ladder touch the wall?
Can you help me break it down it's been a while please thanks.

Mathematics
2 answers:
Sergeeva-Olga [200]4 years ago
8 0
Applying Pythagoras theorum to the situation ;

\alpha ^2 +  \beta ^2 = C^2 \\ \\ 9^2 +  \beta ^2 = 15^2 \\ \\ 81 +  \beta ^2 = 225 \\ \\ =>  \beta ^2 = 144 \\ \\ =>  \beta = 12 cm

Thus, the answer is 12 ft.
lana [24]4 years ago
6 0
The answer is 12 feet tall... look at pic

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Answer:

Step-by-step explanation:

Dimensions of the rectangular park = 4 inches by 6 inches

Since scale factor = \frac{\text{Dimensions of the park on map}}{\text{Dimensions of the original park}} = \frac{1}{30}

\frac{4}{\text{Length of the original park}}=\frac{1}{30}

Length of the original park = 120 miles

Similarly, width of the park = 180 miles

Area of the park = Length × Width

                           = 120 × 180

                           = 21600 square miles

Therefore, area of the original park is 21600 square miles.

Formula for the ratio of area of the park on map and original park is,

\frac{\text{Area of the park on map}}{\text{Area of the original park}}=(\text{Scale factor})^2

\frac{6}{21600}=(\text{Scale factor})^2

Scale factor = \sqrt{\frac{1}{3600}}

                    = \frac{1}{60}

Scale factor to reproduce the map so that it fits in the brochure will be 1 inch for every 60 miles.

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4 years ago
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Answer:

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3 years ago
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12%+5%+15%=

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