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saw5 [17]
3 years ago
14

The lifespans of tigers in a particular zoo are normally distributed. The average tiger lives 22.4 years; the standard deviation

is 2.7 years. Use the empirical rule (68-95-99.7%) to estimate the probability of a tiger living less than 14.31 years.
Mathematics
2 answers:
oksano4ka [1.4K]3 years ago
7 0
P(27.8 < C < 30.5) = P(X>27.8) - P(X> 30.5) =0.025 - 0.0015 = 0.0235 hope this helps:)
liq [111]3 years ago
5 0

Answer:

ok

Step-by-step explanation:

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In the above figure, m∠A = 32° and m∠B = (2x + 14)°. If angles A and B are complementary angles, what are the value of x and the
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2 years ago
Complete the table by filling in the elapsed tine.<br> Help pls
Sav [38]

Answer:

RADIUS

==================================

PROBLEM

Mary’s bicycle wheel has a circumference of 226.08 cm². What is its radius?

SOLUTION

We can solve this problem using the circumference formula in which π stands for ( 3.14 ), C stands for circumference itself and r stands for radius.

\bold{Formula \: || \: C = 2πr}Formula∣∣C=2πr

\tt{226.08 = 2(3.14) r}226.08=2(3.14)r

'Now to find the radius,Substitute 226.08 for c which is circumference in the formula.

\begin{gathered} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \tt{C = 2πr} \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \tt{226.08 = 2(3.14)\red{r}} \\ \\ \: \: \: \: \: \: \: \: \large \tt{ \frac{226.08}{6.28} = \cancel\frac{6.28 \red{r}}{6.28} } \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \boxed{\tt\green{C = 36}}\end{gathered}

C=2πr

226.08=2(3.14)r

6.28

226.08

=

6.28

6.28r

C=36

To check:

\begin{gathered} \small\begin{array}{|c|}\hline \bold{circumference }\\ \\ \tt{C = 2πr} \\ \tt{C = 2(3.14) (36\:cm) } \\ \tt{C = 2(113.04\:cm) } \\ \underline{\tt \green{C = 226.08\:cm }} \\ \hline \end{array} \end{gathered}

circumference

C=2πr

C=2(3.14)(36cm)

C=2(113.04cm)

C=226.08cm

FINAL ANSWER

If Mary's Bicycle has a circumference of 226.08 cm then the radius is 36.

\boxed{ \tt \red{r = 36}}

r=36

==================================

#CarryOnLearning

7 0
2 years ago
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