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3 years ago

(look at the image) can i get help on this?

Mathematics

2 answers:

ser-zykov [4K]3 years ago

6 0

Answer:

no u wont

Step-by-step explanation:

give money

Anna [14]3 years ago

3 0

18. 105 = 2x - 11 —> 116 = 2x —> x = 58

Plug in x — > 2(58) - 11 —> 116 - 11 —> 105

105 + 105 = 210

360 which is the sum of all of the angles

360 - 210 = 150

Now divide 150 by 2 because those 2 angles and vertical angles and they should have the same degrees.

150/2 = 75

Angle AEB = 75 degrees

Angle CED = 75 degrees

Angle BEC = 105 degrees

19. (6x + 19) + x = 180 because they are adjacencies angles and make a straight line which equals 180 degrees

7x + 19 = 180 —> 7x = 161 —> x = 23

Now plug in x —> x = 23 for angle BEC

6(23) + 19 —> 138 + 19 —> 157

Angle BEC = 23 Degrees

Angle AEB =105 Degrees

Angle AED = 23 Degrees

Angle CED = 157 Degrees

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3 years ago

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Answer:

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Step-by-step explanation:

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2 years ago

In a rhombus whose side measures 20 and the smaller angle is 38°. Find the length of the larger diagonal, to the nearest tenth.

Lemur [1.5K]

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3 years ago

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yanalaym [24]

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2 years ago

A circle has a diameter with endpoints at (6, 5) and (8, 5). Write the equation for the circle.

mario62 [17]

Answer:

$(x-7)^2+(y-5)^2=1$

Step-by-step explanation:

The two things that are required to formulate the equation of the circle is the center coordinate and the radius of the circle!

Center of the circle:

The center of the circle always lies at the midpoint of the endpoints of its diameter: Let's call the endpoints A(6,5) and B(8,5).

Using the midpoint formula we'll get:

$(x_m, y_m) = \left(\dfrac{x_1+x_2}{2},\dfrac{y_1+y_2}{2}\right)$

$(x_m, y_m) = \left(\dfrac{6+8}{2},\dfrac{5+5}{2}\right)$

$(x_m, y_m) = (7,5)$

This is the center coordinate of our circle.

Radius:

The radius of the circle is the distance from the center of the circle to any of the endpoints of the diameter (A or B)

We can use the distance formula:

$r = \sqrt{(x_1-x_2)^2+(y_1-y_2)^2}$

$r = \sqrt{(x_1-x_m)^2+(y_1-y_m)^2}$

$r = \sqrt{(6-7)^2+(5-5)^2}$

$r = \sqrt{1^2}$

$r = 1$

Equation of the circle:

The equation is written as:

$(x-a)^2+(y-b)^2=r^2$

here, (a,b) are the center points of the circle

in our case this is $(a,b)=(x_m,y_m)=(7,5)$

and r = 1

$(x-7)^2+(y-5)^2=1^2$

$(x-7)^2+(y-5)^2=1$

This is the equation of the circle!

3 0

3 years ago