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3 years ago

If ISO 400, SS 30, f/5.6 overexposes a picture three stops, what are the correct settings for a good exposure?

Mathematics

1 answer:

Reika [66]3 years ago

6 0

Answer:

ISO 1600

Step-by-step explanation:

"Three stops" means the picture is overexposed by a factor of 2^3 = 8. Each f-stop increase halves the exposure, so increasing from 5.6 through 8 to 11 means you have cut the exposure by a factor of 4 with the f-stop change.

Each halving of the shutter-open time also cuts the exposure in half, so reducing the shutter speed from 1/30 to 1/250 cuts the exposure by a factor of about 8.

The adjustments of shutter speed and f-stop have decreased the exposure by a factor of 4·8 = 32, which is a factor of 4 more than the factor of 8 you needed. (The shutter speed change by itself would have been sufficient.)

So, to compensate for the much smaller exposure, you need faster film, by a factor of 4. The film needs to go from ISO 400 to ISO 1600.

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Quadrilateral PQRS is located at P (0, 1), Q (3, 2), R (4, 0), and S (1, −1). Russell and Jamie have both classified PQRS differ

dybincka [34]

Answer: Jamie

Step-by-step explanation:

Bcuz I took the test and made sure it was Jamie

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3 years ago

Read 2 more answers

Men consume on average 15 grams of protein a day. Assume a normal distribution with a standard deviation of 3 grams. A sample of

tatyana61 [14]

Using the normal distribution, there is a 0.4826 = 48.26% probability that the sample mean is between 15 and 16 grams per day.

<h3>Normal Probability Distribution</h3>

The z-score of a measure X of a normally distributed variable with mean $\mu$ and standard deviation $\sigma$ is given by:

$Z = \frac{X - \mu}{\sigma}$

The z-score measures how many standard deviations the measure is above or below the mean.

Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.

By the Central Limit Theorem, the sampling distribution of sample means of size n has standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

For this problem, the parameters are given as follows:

$\mu = 15, \sigma = 3, n = 40, s = \frac{3}{\sqrt{40}} = 0.4743$

The probability is the <u>p-value of Z when X = 16 subtracted by the p-value of Z when X = 15</u>, hence:

X = 16:

$Z = \frac{X - \mu}{\sigma}$

By the Central Limit Theorem

$Z = \frac{X - \mu}{s}$

$Z = \frac{16 - 15}{0.4743}$

Z = 2.11

Z = 2.11 has a p-value of 0.9826.

X = 15:

$Z = \frac{X - \mu}{s}$

$Z = \frac{15 - 15}{0.4743}$

Z = 0

Z = 0 has a p-value of 0.5.

0.9826 - 0.5 = 0.4826 = 48.26% probability that the sample mean is between 15 and 16 grams per day.

More can be learned about the normal distribution at brainly.com/question/15181104

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4 0

2 years ago

When a baseball is hit by a batter the height of the ball age of T at time TT equals zero is determined by the equation age of T

Luda [366]

Answer:

1 ≥ t ≤ 3

Step-by-step explanation:

Given

h(t) = -16t² + 64t + 4

Required

Determine the interval which the bar is at a height greater than or equal to 52ft

This implies that

h(t) ≥ 52

Substitute -16t² + 64t + 4 for h(t)

-16t² + 64t + 4 ≥ 52

Collect like terms

-16t² + 64t + 4 - 52 ≥ 0

-16t² + 64t - 48 ≥ 0

Divide through by 16

-t² + 4t - 3 ≥ 0

Multiply through by -1

t² - 4t + 3 ≤ 0

t² - 3t - t + 3 ≤ 0

t(t - 3) -1(t - 3) ≤ 0

(t - 1)(t - 3) ≤ 0

t - 1 ≤ 0 or t - 3 ≤ 0

t ≤ 1 or t ≤ 3

Rewrite as:

1 ≥ t or t ≤ 3

Combine inequality

1 ≥ t ≤ 3

5 0

2 years ago

How can you use models to explain why 3.1 = 3.10

Andrej [43]

3.1 is like a example when it is hiding a zero behind it and you find this when you do a math problem and you don't put zero in front of a number like 100-89 you don't write "011" so that is why it is like that

4 0

3 years ago

Pieces of Mail. The number of pieces of mail

Zina [86]

Answer:

20.8%

Step-by-step explanation:

The number of the pieces of mail handled by the U.S postal service decreased from 212,000,000,000 to 168,000,000

Therefore the percentage decrease can be calculated as follows

= 212,000,000,000-168,000,000,000

= 44,000,000,000/212,000,000,000 × 100

= 0.2075 × 100

= 20.8 %

Hence the percentage decrease is 20.8%

5 0

3 years ago