Answer:
No, it is not a square
Step-by-step explanation:
If one wall is 19", that would mean the wall perpendicular to this wall is also 19" (in fact all of the walls would be 19"!) If this was a square, then the diagonal we draw at 20.62" would serve as the hypotenuse of a right triangle. One wall would serve as a leg, and another wall as another leg. If this is a square, then the Pythagorean's Theorem would be satisfied when we plug in the 2 wall measures for a and b, and the diagonal for c:
![19^2+19^2=20.62^2](https://tex.z-dn.net/?f=19%5E2%2B19%5E2%3D20.62%5E2)
We need to see if this is a true statement. If the left side equals the right side, then the 2 legs of the right triangle are the same length, and the room, then is a square.
361 + 361 = 425.1844
Is this true? Does 722 = 425.1844? Definitely not. That means that the room is not a square.
The domain is (-3,0) U (2,4)
The range is (-2,-1) U (1,2)
The answer is 0,4,known ás the answer C
Answer:
(
a
−
1
+
b
)(
a
−
1
−
b
)
.
The answer might be: d.) infinite.