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Sati [7]
3 years ago
8

If events A and B are mutually exclusive, P(A or B) = 0.5, and P(B) = 0.3; then what is P(A)?

Mathematics
1 answer:
11Alexandr11 [23.1K]3 years ago
4 0

Answer:

P(A) = 0.2

Step-by-step explanation:

We have that:

P(A) = P(a) + P(A \cap B)

In which P(a) is the probability of a but not b and P(A \cap B) is the probability of both A and B.

By the same logic, we have that:

P(B) = P(b) + P(A \cap B)

Also

P(A or B) is

P(A \cup B) = P(a) + P(b) + P(A \cap B)

Events A and B are mutually exclusive

This means that P(A \cap B) = 0

P(B) = 0.3 = P(b)

P(A \cup B) = P(a) + P(b) + P(A \cap B)

0.5 = P(a) + 0.3

P(a) = 0.2

P(A) = P(a) + P(A \cap B) = 0.2 + 0 = 0.2

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