I´m pretty sure that the terms would just be 3, 4, and 5. It depends what kind of problem it is.
The correct answer is: [A]: " 6 to the power of (1 over 6) " .
Explanation:
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√ [(∛6)] = √ [6⁽¹/³⁾ ] = [6⁽¹/²⁾ ] ⁽¹/³⁾ = 6^ ( ⁽¹/²⁾ * ⁽¹/³⁾ ) = ???? ;
<u>Note</u>: ;
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→ 6^ ( ⁽¹/²⁾ * ⁽¹/³⁾ ) ;
= 6^ ( ⁽¹/⁶⁾ ) ;
→ which is: Answer choice: [A]: " 6 to the power of (1 over 6) " .
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Answer:
no
Step-by-step explanation:
Look at the axis graph. If both of the coordinates are negative, it would be in quadrant lll. If you go over to the x-axis, you would be in quadrant lV, or 4.
(-2,-3) -> (2,-3)
You change the x-factor's sign.
I hope this helps!
~kaikers
Answer:
11
Step-by-step explanation:
Substitute the given values into the expression
3² + 3(8) ÷ 2 - 2(5)
= 9 + 24 ÷ 2 - 10 ← evaluate division before addition/ subtraction
= 9 + 12 - 10
= 21 - 10
= 11